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Chapter 27: Problem 3

Differentiate between stepwise stability constants and overall stability constants.

Short Answer

Expert verified
The key difference between stepwise and overall stability constants is that stepwise constants refer to the equilibrium constants of each individual step in a complex formation, whereas the overall constant refers to the cumulative equilibrium constant for the formation of the complete complex.

Step by step solution

01

Define Stepwise Stability Constants

Stepwise stability constants are the equilibrium constants for each step of a complex formation. It's important to keep in mind that many complex ions are formed in a stepwise manner, and each step has its own equilibrium constant which is referred to as the 'stepwise stability constant'.
02

Define Overall Stability Constants

The Overall (Cumulative) Stability Constant refers to the equilibrium constant for the formation of a complex from the metal ion and the ligands, taken to all be in their initial unassociated states. It gives the stability of the complete complex, showing how strongly the complete complex is formed.
03

Differentiate Between Stepwise Stability Constants and Overall Stability Constants

After understanding both these terms, the differences can be highlighted. The main difference between stepwise and overall stability constants lies in their relationship with the complex ion formation: 1. Stepwise stability constant refers to the equilibrium constant for each individual process of complex ion formation. 2. Overall stability constant refers to the cumulative equilibrium constant for the complete process of complex ion formation from its constituent ions.

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Most popular questions from this chapter

(a) What are nucleophilic substitution reactions in coordination compounds? (b) Discuss the dissociative and association mechanism for octahedral complexes.

Discuss the mechanism for substitution in square planar complexes fo platinum (II).

Discuss the inner-sphere mechanism for electron transfer reaction with the help of a suitable example.

Account for the following: (a) \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{4}\right]^{2+}\) gives trans \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\) with \(\mathrm{Cl}^{-}\) while \(\left[\mathrm{PtCl}_{4}\right]^{2-}\) on treatment with \(\mathrm{NH}_{3}\) gives cis \(\left[\mathrm{Pt}\left(\mathrm{NH}_{3}\right)_{2} \mathrm{Cl}_{2}\right]\) (b) \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)\right]^{3+}\) is inert but \(\left[\mathrm{Cr}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{2+}\) is labile towards ligand substitution reactions.

What are electron-transfer reactions? How do the one-election and two-electron transfer reactions differ from each other?
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