Chapter 32: Problem 8

Draw the structure of: (a) Polymeric gold (I) iodidie (b) Iron derivative of Schiff's base

Short Answer

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The structure of Polymeric Gold (I) Iodide is a coordination polymer consisting of [AuI2]- ions linked by aurophilic interactions. Whereas, the structure of the Iron derivative of Schiff base typically forms a complex having square planar or octahedral structure, often forming two-five membered rings with the iron atom.

Step by step solution

Drawing Structure of Polymeric Gold (I) Iodide

Polymeric gold (I) iodide consists of linear chains of [AuI2]- ions linked by aurophilic interactions. Each gold atom is square planar coordinated, with two iodide ions and bounded by two other gold atoms in linear configuration in the chain. Draw a linear chain with interspersed gold and iodine atoms, the gold being connected to two iodine atoms and two other gold atoms in a linear chain structure. The chains run parallel to each other, forming layers.

Drawing Structure of Iron Derivative of Schiff's Base

Schiff's base is typically used in the synthesis of metal complexes. When coordinated with iron, the derived complex often forms square planar or octahedral structures, depending on the oxidation state of the metal. Here, without the presence of a specific Schiff base structure or the oxidation state of iron, the structure cannot be accurately determined. But in a typical scenario, a Schiff base ligand containing a nitrogen atom forms two-five membered rings with the central iron atom, usually resulting in an octahedral geometry.

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Draw the structure of: (a) Polymeric gold (I) iodidie (b) Iron derivative of Schiff's base

Short Answer

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Drawing Structure of Polymeric Gold (I) Iodide

Drawing Structure of Iron Derivative of Schiff's Base

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