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Chapter 6: Problem 7

Predict the behaviour of each of the following in water, liquid \(\mathrm{NH}_{3}\) and liquid \(\mathrm{SO}_{2}\). (a) \(\mathrm{NH}_{4} \mathrm{Br}\) (b) \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\)

Short Answer

Expert verified
Both \(\mathrm{NH}_{4} \mathrm{Br}\) and \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) will be soluble in water and liquid ammonia, but likely display limited solubility in liquid sulfur dioxide.

Step by step solution

01

Solubility in water

Analyse the solubility in water. First, looking at \(\mathrm{NH}_{4} \mathrm{Br}\). Since it's a salt of ammonium (\(\mathrm{NH}_{4}^{+}\)), it is soluble in water. It will therefore dissociate into its ions. For \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\), this molecule will also be soluble in water because it's an amide, which can form hydrogen bonds with water.
02

Solubility in \(NH_3\)

Next, evaluate the solubility in liquid ammonia. \(\mathrm{NH}_{4} \mathrm{Br}\) being a salt of ammonium (\(\mathrm{NH}_{4}^{+}\)), will also be soluble in liquid ammonia. It will dissociate into \(NH_4^+ \) and \( Br^- \) ions. Similarly, the amide \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) can form hydrogen bonds with ammonia molecules, which means it will also be soluble.
03

Solubility in \(SO_2\)

Finally, consider the solubility in liquid sulfur dioxide. This is tricky, because liquid sulfur dioxide is a nonpolar solvent, while both \(\mathrm{NH}_{4} \mathrm{Br}\) and \(\mathrm{CH}_{3} \mathrm{COONH}_{4}\) are polar compounds. Polar compounds generally have limited solubility in nonpolar solvents, so it can be expected that this will be the case here.

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Most popular questions from this chapter

What do you mean by levelling and differentiating solvents?

Give an account of each of the following in liquid \(\mathrm{NH}_{3}\). (a) Acid-base reaction (b) Metathesis reaction (c) Ammonolysis (d) Complex formation reaction

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Discuss the important characteristics of solvents.

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