Chapter 9: Problem 7

Write complete balanced equations for the following: (a) \(\mathrm{Al}+\mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O}(\mathrm{b}) \mathrm{LiAlH}_{4}+\mathrm{SnCl}_{4}\) (c) \(\mathrm{CaH}_{2}+\mathrm{CH}_{3} \mathrm{OH}\) (d) \(\mathrm{Cd}\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)+\mathrm{LiAlH}_{4}\)

Short Answer

Expert verified

Balanced equations are: (a) 2Al + 2NaOH + 6H2O \(\rightarrow\) 2NaAlO2 + 3H2 (b) LiAlH4 + 4SnCl4 \(\rightarrow\) 4LiCl + AlCl3 + 4Sn + 2H2 (c) CaH2 + 2CH3OH \(\rightarrow\) Ca(OH)2 + 2CH4 (d) Cd(C2H3)2 + 2LiAlH4 \(\rightarrow\) CdH2 + 2Al + 2Li + 2C2H4.

Step by step solution

Balancing Equation (a)

To balance Al + NaOH + H2O, first look at the reaction. The product for this type of reaction is usually Al(OH)3 + Na + H2, but we can see that the sodium (Na) does not match up. Instead, we'll end up with NaAlO2 + H2. Now we can balance the equation as: 2Al + 2NaOH + 6H2O \(\rightarrow\) 2NaAlO2 + 3H2. This ensures there is equilibrium both sides of the equation.

Balancing Equation (b)

This equation involves a reaction between LiAlH4 and SnCl4. Breaking down the reactants and reformed products in this reaction would give us LiCl, AlCl3, and H2. Balancing this equation would look like this: LiAlH4 + 4SnCl4 \(\rightarrow\) 4LiCl + AlCl3 + 4Sn + 2H2.

Balancing Equation (c)

With CaH2 and CH3OH. In the result we have Ca(OH)2 as calcium will take up the hydroxide to form a base, and CH4 as a byproduct. Balancing the equation we get:CaH2 + 2CH3OH \(\rightarrow\) Ca(OH)2 + 2CH4.

Balancing Equation (d)

The equation consists of Cd(C2H3)2 and LiAlH4. The result of this reaction would yield CdH2, Al, Li, and C2H4. Balancing the equation gives,Cd(C2H3)2 + 2LiAlH4 \(\rightarrow\) CdH2 + 2Al + 2Li + 2C2H4.

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Write complete balanced equations for the following: (a) \(\mathrm{Al}+\mathrm{NaOH}+\mathrm{H}_{2} \mathrm{O}(\mathrm{b}) \mathrm{LiAlH}_{4}+\mathrm{SnCl}_{4}\) (c) \(\mathrm{CaH}_{2}+\mathrm{CH}_{3} \mathrm{OH}\) (d) \(\mathrm{Cd}\left(\mathrm{C}_{2} \mathrm{H}_{5}\right)+\mathrm{LiAlH}_{4}\)

Short Answer

Step by step solution

Balancing Equation (a)

Balancing Equation (b)

Balancing Equation (c)

Balancing Equation (d)

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