Write a balanced chemical equation for the reactions given below: a. When hydrogen gas reacts is combined with oxygen gas and the mixture ignited with a spark, water is formed in a violent reaction. b. Lead (IV) oxide reacts with HCl to give lead (II) chloride, chlorine gas and water. c. Solid potassium chlorate decomposes on heating to form solid KCl and oxygen gas.

Short Answer

Expert verified
a. \(2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O}\) b. \(\text{PbO}_2 + 4\text{HCl} \rightarrow \text{PbCl}_2 + \text{Cl}_2 + 2\text{H}_2\text{O}\) c. \(2\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2\)

Step by step solution

01

Balancing Reaction a

Write the unbalanced chemical equation for the reaction of hydrogen gas (H2) with oxygen gas (O2) to form water (H2O): \[ \text{H}_2 + \text{O}_2 \rightarrow \text{H}_2\text{O} \]. Balance the number of H atoms and O atoms on both sides of the reaction. Since there are 2 H atoms in H2O on the right and 2 in H2 on the left, the H atoms are balanced. For the O atoms, there is 1 O2 molecule on the left and only half of an O2 molecule (as each H2O contains only 1 O atom) on the right, so put a coefficient of 2 in front of H2O: \[ \text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \]. Lastly, ensure that the O atoms are balanced by putting a coefficient of 2 in front of the H2, which gives us the balanced equation: \[ 2\text{H}_2 + \text{O}_2 \rightarrow 2\text{H}_2\text{O} \].
02

Balancing Reaction b

The unbalanced chemical equation for the reaction of lead (IV) oxide (PbO2) with hydrochloric acid (HCl) is: \[ \text{PbO}_2 + \text{HCl} \rightarrow \text{PbCl}_2 + \text{Cl}_2 + \text{H}_2\text{O} \]. Begin by balancing the lead atoms: there is 1 Pb on both sides, so they are balanced. Next, balance the chlorine atoms: there are 2 Cl atoms in PbCl2 and 1 in Cl2, giving a total of 3 Cl atoms on the right. To balance, put a coefficient of 4 in front of HCl: \[ \text{PbO}_2 + 4\text{HCl} \rightarrow \text{PbCl}_2 + \text{Cl}_2 + \text{H}_2\text{O} \]. Now there are 4 H atoms on the left and 2 on the right, so put a coefficient of 2 in front of H2O. Finally, the oxygen atoms are balanced with 2 O on both sides. The balanced equation is: \[ \text{PbO}_2 + 4\text{HCl} \rightarrow \text{PbCl}_2 + \text{Cl}_2 + 2\text{H}_2\text{O} \].
03

Balancing Reaction c

Write the unbalanced chemical equation for the decomposition of solid potassium chlorate (KClO3) to form solid KCl and oxygen gas (O2): \[ 2\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2 \]. Balance the K atoms: there are 2 K atoms on both sides. Move on to Cl atoms, with 2 Cl atoms on both sides as well. Finally, balance the O atoms; there are 6 O atoms in the reactants (2 KClO3) and 6 in the products (3 O2). The balanced equation then is: \[ 2\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2 \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reaction
A chemical reaction is a process where substances, known as reactants, are transformed into different substances called products. This transformation occurs as a result of the breaking and forming of chemical bonds. Consider the example of burning hydrogen gas in the presence of oxygen, which is reaction (a) from the exercise. When ignited, hydrogen and oxygen react violently to form water, showcasing the exothermic nature of the reaction where energy, in the form of heat or light, is also released.

Understanding chemical reactions is foundational to the study of chemistry, as they explain how new substances are formed and can illustrate the conservation of matter, where the total mass of reactants equals the total mass of products.
Stoichiometry
Stoichiometry is essentially the arithmetic of chemistry. It involves the calculation of the quantitative (measurable and numerical) relationships of the elements and compounds as they participate in chemical reactions. The term comes from the Greek words 'stoicheion' (element) and 'metron' (measure). For instance, when balancing reaction (c), the stoichiometry of the decomposition of potassium chlorate is taken into account to ensure that the number of atoms for each element is preserved on both sides of the equation.

Proper stoichiometry is crucial for predicting the amounts of products formed in a given chemical reaction or the amounts of reactants needed for a reaction to proceed completely. This concept is not only central to the field of chemistry but also critically important in various practical applications such as pharmaceuticals, environmental engineering, and industrial chemistry.
Chemical Equation
A chemical equation is a symbolic representation of a chemical reaction where the reactants are placed on the left side and the products on the right, separated by an arrow indicating the direction of the reaction. For example, in reaction (b), the lead (IV) oxide reacts with HCl to give lead (II) chloride, chlorine gas, and water, depicted by the equation \[ \text{PbO}_2 + 4\text{HCl} \rightarrow \text{PbCl}_2 + \text{Cl}_2 + 2\text{H}_2\text{O} \].

A balanced chemical equation ensures that the number of atoms for each element is the same on both sides, adhering to the law of conservation of mass. Balancing equations is a fundamental skill in chemistry that enables scientists and students to understand the ratio in which substances react and form products.
Decomposition Reaction
A decomposition reaction is a type of chemical reaction in which a single compound breaks down into two or more simpler substances. This breakdown can be induced by heat, light, or electricity. In the context of our exercise, reaction (c) is a classic example, where solid potassium chlorate decomposes upon heating to form solid potassium chloride and oxygen gas. The balanced chemical equation, \[ 2\text{KClO}_3 \rightarrow 2\text{KCl} + 3\text{O}_2 \], illustrates how the breakdown of one compound, potassium chlorate, leads to the formation of two distinct products, showcasing the principle of a decomposition reaction.

Decomposition reactions are often used to extract metals from their ores or to produce simpler substances as precursors for further chemical processing. Understanding and balancing these reactions are vital in both academic and applied chemical studies.

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Most popular questions from this chapter

Mixing each of the following salt solutions results in the formation of a precipate. In each case, identify the insoluble salt. a. \(\mathrm{NaCl}+\mathrm{Pb}\left(\mathrm{NO}_{3}\right) 2\) b. \(\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right) 3+\mathrm{KOH}\) c. \(\mathrm{Ca}\left(\mathrm{NO}_{3}\right)_{2}+\mathrm{K}_{2} \mathrm{SO}_{4}\) d. \(\mathrm{Li}_{2} \mathrm{~S}+\mathrm{CuSO}_{4}\) e. \(\mathrm{Co}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{2}+\mathrm{LiOH}\)

Arsonic and nitric acids react to form nitrogen monoxide, arsenic acid and water according to the equation shown below. Is this an example of a redox reaction? \(2 \mathrm{HNO}_{3}(a q)+3 \mathrm{H}_{3} \mathrm{AsO}_{3}(a q) \rightarrow 2 \mathrm{NO}(g)+3 \mathrm{H}_{3} \mathrm{AsO}_{4}(a q)+\mathrm{H}_{2} \mathrm{O}(\mathrm{l})\)

For each of the reactions given below, calculate the oxidation number of each of the elements in the reactants and the products and determine if the reaction involves oxidation-reduction. If it is a redox reaction, identify the elements that have been oxidized and reduced. a. \(\mathrm{Cu}_{2} \mathrm{~S} \rightarrow 2 \mathrm{Cu}+\mathrm{S}\) Reactants: Cu ___________ \(\mathrm{S}\) ___________ Products: Cu ___________ \(\mathrm{S}\) ___________ Element oxidized: ___________ Element Reduced ___________ b. \(\mathrm{CaCO}_{3} \rightarrow \mathrm{CaO}+\mathrm{CO}_{2}\) Reactants: Ca ___________ C ___________ O ___________ Products: \(\mathrm{Ca}\) ___________ \(C\) ___________ O ___________ Element oxidized: ___________ Element Reduced ___________ c. \(\mathrm{Fe}_{2} \mathrm{O}_{3}+3 \mathrm{H}_{2} \rightarrow 2 \mathrm{Fe}+3 \mathrm{H}_{2} \mathrm{O}\) Reactants: Fe ___________ O ___________ \(\mathrm{H}\) ___________ Products: Fe ___________ O ___________ \(\mathrm{H}\) ___________ Element oxidized: ___________ Element Reduced ___________ \(\mathrm{d} . \mathrm{AgNO}_{3}+\mathrm{NaCl} \rightarrow \mathrm{AgCl}(\mathrm{s})+\mathrm{NaNO}_{3}\) Reactants: Ag ___________ \(\mathrm{N}\) ___________ \(\mathrm{O}\) ___________ \(\mathrm{Na}\) ___________ \(\mathrm{Cl}\) ___________ Products: \(\mathrm{Ag} \) ___________ \( \mathrm{N}\) ___________ \( \mathrm{O}\) ___________ \( \mathrm{Na}\) ___________ Element oxidized: ___________ Element Reduced ___________

a. Write a chemical equation for the reaction of solid iron with solid sulfur to form solid iron(II) sulfide. b. Write a chemical equation for the reaction of solid carbon with solid magnesium oxide to form carbon monoxide gas and magnesium metal.

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