The Harber process is used making ammonia from nitrogen and hydrogen according to the equation shown below. The yield of the reaction, however, is not \(100 \%\). a. Suppose you end up with \(6.2\) moles of ammonia, but the reaction stoichiometry predicts that you should have \(170.0\) grams of ammonia. What is the percent yield for this reaction? b. If you started with \(6.2\) grams of nitrogen and you produce \(6.2\) grams of ammonia what would be the percent yield?

Short Answer

Expert verified
The percent yield for reaction (a) is 62%. For reaction (b), the percent yield would require applying the stoichiometry conversion from N2 to NH3 and may result in a different value, depending on the theoretical yield calculated in grams.

Step by step solution

01

Convert the predicted ammonia mass to moles

To find the percent yield, we first need to convert the predicted mass of ammonia (170.0 grams) to moles using the molar mass of ammonia (NH3) which is approximately 17 g/mol. The conversion is given by: \( \text{moles of NH3} = \frac{\text{mass of NH3}}{\text{molar mass of NH3}} = \frac{170.0\text{ g}}{17\text{ g/mol}} \).
02

Calculate the theoretical yield in moles

Carrying out the calculation from Step 1, we get the theoretical yield in moles: \( \frac{170.0\text{ g}}{17\text{ g/mol}} = 10 \text{ moles of NH3} \). This is the amount of ammonia we would expect if the reaction had 100% yield.
03

Calculate the percent yield

The percent yield can be found using the equation: \( \text{percent yield} = \frac{\text{experimental yield}}{\text{theoretical yield}} \times 100\% \).Plug in the experimental yield of 6.2 moles and the theoretical yield of 10 moles to obtain: \( \text{percent yield} = \frac{6.2\text{ mol}}{10\text{ mol}} \times 100\% = 62\% \).
04

Calculate the molar mass of nitrogen

The molar mass of nitrogen (N2) is approximately 28 g/mol. We will use this in the next step to find the theoretical yield.
05

Convert starting nitrogen mass to moles

Calculate the moles of nitrogen used to start the reaction: \( \text{moles of N2} = \frac{\text{mass of N2}}{\text{molar mass of N2}} = \frac{6.2\text{ g}}{28\text{ g/mol}} \).
06

Calculate the theoretical yield of ammonia from nitrogen

Based on the stoichiometry of the reaction (1 mole of N2 gives 2 moles of NH3), calculate the theoretical yield of ammonia: \( \text{theoretical yield of NH3} = 2 \times \text{moles of N2} \).Since the molar ratio in the balanced equation for N2: NH3 is 1:2, multiply the moles of N2 obtained in Step 5 by 2.
07

Calculate the percent yield for part (b)

Use your results from Step 5 and the molar mass of NH3 to find the theoretical yield of NH3 in grams. Then, use the percent yield formula as in Step 3 to find the actual percent yield with 6.2 grams of ammonia produced: \( \text{percent yield} = \frac{\text{experimental yield (in grams)}}{\text{theoretical yield (in grams)}} \times 100\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry is a branch of chemistry that deals with the quantitative relationships between the reactants and products in a chemical reaction. In essence, it's about balancing equations and using these balances to predict the amount of substance required or produced in a reaction.

For instance, when examining a reaction such as the Haber Process, stoichiometry informs us of the proportional relationship between nitrogen (N2), hydrogen (H2), and ammonia (NH3). This ratio is crucial when trying to determine the theoretical and experimental yields of a reaction. Knowing how to perform stoichiometric calculations enables students to grasp how much of each reactant is required to produce a certain amount of product.
Molar Mass
The molar mass of a substance is the mass of one mole of that substance. It is a physical property that is of particular interest in the study of stoichiometry, as it provides a link between the mass of a substance and the number of particles or moles present. Molar mass is usually expressed in grams per mole (g/mol).

In the provided exercise, the molar mass of ammonia (NH3) is 17 g/mol. This means that one mole of ammonia weighs 17 grams. For nitrogen (N2), the molar mass is 28 g/mol. These molar masses are essential in converting between moles and grams, which is a common step in stoichiometry when working out percentages or predicting yields.
Theoretical Yield
The theoretical yield is the maximum amount of product that can be produced in a chemical reaction based on the amount of limiting reactant, assuming complete conversion and no side reactions. This yield is called 'theoretical' because it's what we would expect if everything happens perfectly, which is rarely the case in practical settings.

The steps in calculating the theoretical yield involve using the balanced chemical equation to figure out the mol-to-mol relationship between reactants and products. In the example of the Haber process, the theoretical yield of ammonia is determined by using the stoichiometric ratios between nitrogen, hydrogen, and ammonia.
Experimental Yield
The experimental yield is the actual amount of product obtained from a chemical reaction, which is often less than the theoretical yield due to various practical factors such as incomplete reactions, side reactions, or loss of product during the process.

Calculating the percentage yield requires both the experimental yield and the theoretical yield. It's a measure of the efficiency of the reaction, telling us how much of the theoretical yield was actually achieved. The percent yield formula, shown in the exercise solution, illustrates how to compare the experimental yield (i.e., the actual, observed result) to the theoretical prediction.
Haber Process
The Haber process is an industrial method for the synthesis of ammonia from nitrogen and hydrogen gas. This reaction plays a significant role in modern agriculture, as ammonia is a key precursor to fertilizers. The balanced chemical equation for the Haber process is N2 + 3H2 ↔ 2NH3. Despite its apparent simplicity, the Haber process is a dynamic equilibrium, with several factors affecting the yield of ammonia.

When calculating yields for reactions like the Haber process, it's vital to understand that the actual (experimental) yield will often be lower than the one predicted stoichiometrically (theoretical yield). The percent yield calculation allows us to measure the efficiency of the reaction in converting reactants to desired products under real-world conditions.

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