Calculating \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) and \(\left[\mathrm{HO}^{-}\right]\) using \(\mathrm{K} \mathrm{W}\) 1\. A solution at \(25^{\circ} \mathrm{C}\), is known to have a hydronium ion concentration of \(4.5 \times 10^{-5} \mathrm{M}\); what is the concentration of hydroxide ion in this solution? 2\. A solution at \(25^{\circ} \mathrm{C}\), is known to have a hydroxide ion concentration of \(7.5 \times 10^{-2} \mathrm{M}\); what is the concentration of hydronium ion in this solution? 3\. A solution is known to have a hydronium ion concentration of \(9.5 \times 10^{-8} \mathrm{M}\); what is the concentration of hydroxide ion in this solution?

Short Answer

Expert verified
\(\left[\mathrm{HO}^{-}\right]\) for part 1 is \(2.22 \times 10^{-10} \mathrm{M}\); \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) for part 2 is \(1.33 \times 10^{-13} \mathrm{M}\); \(\left[\mathrm{HO}^{-}\right]\) for part 3 is \(1.05 \times 10^{-7} \mathrm{M}\).

Step by step solution

01

Understanding \(K_{W}\)

The ion-product constant for water, or \(K_{W}\), is the product of the concentrations of hydronium \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) and hydroxide \(\left[\mathrm{HO}^{-}\right]\) ions in water at a given temperature. At \(25^\circ\mathrm{C}\), \(K_{W} = 1.0 \times 10^{-14}\).
02

Find the concentration of \(\left[\mathrm{HO}^{-}\right]\) for part 1

Use the formula \(K_{W} = \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\left[\mathrm{HO}^{-}\right]\) and solve for \(\left[\mathrm{HO}^{-}\right]\) by dividing \(K_{W}\) by the given hydronium ion concentration. \([\mathrm{HO}^{-}] = \frac{1.0 \times 10^{-14}}{4.5 \times 10^{-5}} = 2.22 \times 10^{-10} \mathrm{M}\).
03

Find the concentration of \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) for part 2

Given the hydroxide ion concentration, use \(K_{W} = \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\left[\mathrm{HO}^{-}\right]\) to find \(\left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\) by dividing \(K_{W}\) by the given hydroxide ion concentration. \([\mathrm{H}_{3} \mathrm{O}^{+}] = \frac{1.0 \times 10^{-14}}{7.5 \times 10^{-2}} = 1.33 \times 10^{-13} \mathrm{M}\).
04

Find the concentration of \(\left[\mathrm{HO}^{-}\right]\) for part 3

Again, use \(K_{W} = \left[\mathrm{H}_{3} \mathrm{O}^{+}\right]\left[\mathrm{HO}^{-}\right]\) to find \(\left[\mathrm{HO}^{-}\right]\), using the given hydronium ion concentration for part 3. \([\mathrm{HO}^{-}] = \frac{1.0 \times 10^{-14}}{9.5 \times 10^{-8}} = 1.05 \times 10^{-7} \mathrm{M}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ion-Product Constant for Water
Understanding the Ion-Product Constant for Water, known as \(K_W\), is crucial for anyone studying chemistry, particularly when examining acid-base reactions. At a certain temperature, this constant represents the equilibrium concentration of water molecules dissociated into hydronium (\([H_3O^+]\)) and hydroxide (\([OH^-]\)) ions.

At the significant temperature of \(25^\circ\mathrm{C}\), \(K_W\) is valued at \(1.0 \times 10^{-14}\). This value is derived from the principle that water is in a dynamic equilibrium where water molecules dissociate into ions and ions recombine to form water molecules at equal rates. When the concentrations of \([H_3O^+]\) and \([OH^-]\) are multiplied, the result remains constant at \(K_W\), provided that the temperature is stable.

This relationship is key in determining the properties of solutions, understanding the pH scale, and assessing the acid or base nature of a substance. In an ideal neutral solution, the concentrations of \([H_3O^+]\) and \([OH^-]\) are equivalent, which also explains why pure water has a neutral pH of 7.
Hydronium Ion Concentration
The hydronium ion concentration in a solution, represented as \([H_3O^+]\), is an important parameter in the field of acid-base chemistry. It indicates the concentration of hydrogen ions present in a solution, which directly affects the solution's acidity. A higher \([H_3O^+]\) corresponds to a more acidic solution, while a lower concentration suggests a more alkaline solution.

To find the \([H_3O^+]\) in a solution when the \([OH^-]\) is known, we use the \(K_W\) value and the expression \(K_W = [H_3O^+][OH^-]\). Algebraic manipulation allows us to isolate \([H_3O^+]\) and calculate its value. For instance, if a solution at \(25^\circ\mathrm{C}\) has an \([OH^-]\) of \(7.5 \times 10^{-2} \mathrm{M}\), the \([H_3O^+]\) can be calculated by dividing \(K_W\) by the known \([OH^-]\), thus helping to classify the solution as acidic or basic.
Hydroxide Ion Concentration
Likewise, the hydroxide ion concentration, denoted as \([OH^-]\), gives us an insight into the alkalinity of a solution. It is the counterpart to the hydronium ion concentration and an increase in \([OH^-]\) means a decrease in the solution's acidity, making it more basic or alkaline.

To find the \([OH^-]\) when \([H_3O^+]\) is given, one simply needs to rearrange the equilibrium expression for water. For example, if the hydronium ion concentration is \(4.5 \times 10^{-5} \mathrm{M}\), the hydroxide ion concentration can be found by dividing \(K_W\) by this value of \([H_3O^+]\). This is an essential method in understanding the full composition of a solution and predicting its behavior in acid-base reactions.
Acid-Base Equilibrium
The concept of Acid-Base Equilibrium is central to understanding the balance between acidic and basic ions in a solution. When an acid donates a proton (H+), it increases the \([H_3O^+]\), whereas a base accepts a proton, increasing the \([OH^-]\). Equilibrium is the state where the rate of proton donation by acids equals the rate of proton acceptance by bases.

At equilibrium in pure water or a neutral solution, the concentrations of the hydronium and hydroxide ions are equal. However, in a solution where an acid or base has been added, the equilibrium shifts to re-establish the balance, leading to changes in ion concentrations until a new equilibrium is achieved. Understanding this dynamic is fundamental for predicting the direction of the reaction and calculating the pH of various substances in solution.

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Most popular questions from this chapter

1\. A solution is known to have a hydronium ion concentration of \(4.5 \times 10^{-5} \mathrm{M}\); what is the \(p \mathrm{H}\) this solution? 2\. A solution is known to have a \(p \mathrm{H}\) of \(9.553\); what is the concentration of hydronium ion in this solution? 3\. A solution is known to have a hydronium ion concentration of \(9.5 \times 10^{-8} \mathrm{M}\); what is the \(p \mathrm{H}\) this solution? 4\. A solution is known to have a pH of \(4.57\); what is the hydronium ion concentration of this solution?

1\. You are given a solution containing an unknown concentration of HCl. You carefully measure \(50.0 \mathrm{~mL}\) of this solution into a flask and then add a few drops of phenolphthalein solution. You prepare a buret containing \(0.055 \mathrm{M} \mathrm{NaOH}\) and note that the initial level of the solution in the buret is \(12.6 \mathrm{~mL}\). You slowly add the \(\mathrm{NaOH}\) solution to the acid until the color change just occurs (as evidence of the color change becomes visible, you carefully stir the solution after each drop has been added). When the acid solution turns (and remains) pink, you note that the volume in the buret is now \(28.9 \mathrm{~mL}\). What is the concentration of the unknown acid solution? 2\. If \(25.00 \mathrm{~mL}\) of \(\mathrm{HCl}\) solution with a concentration of \(0.1234 \mathrm{M}\) is neutralized by \(23.45 \mathrm{~mL}\) of \(\mathrm{NaOH}\), what is the concentration of the base?

1\. For each of the following, write a balanced neutralization equation: a. The reaction of calcium hydroxide with hydrochloric acid. b. The reaction of sodium hydroxide with sulfuric acid (both ionizations). c. The reaction of barium hydroxide with nitric acid. 2\. Write a balanced neutralization equation for the reaction of calcium hydroxide with sulfuric acid

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