The value of the proportionality constant \(R\), can be calculated from the fact that exactly one mole of a gas at exactly 1 atm and at 0 "C \((273 \mathrm{~K})\) has a volume of \(22.414 \mathrm{~L}\). Solution Substituting in the equation: $$ \begin{array}{c} P V=n R T \text { or } R=\frac{P V}{n T} \\ R=\frac{(1 a t m)(22.414 L)}{(1 m o l e)(273 K)}=0.082057 L \text { atm } m o l^{-1} K^{-1} \end{array} $$

Short Answer

Expert verified
The value of the gas constant R is 0.082057 L atm mol^-1 K^-1.

Step by step solution

01

Understand the Ideal Gas Law

The Ideal Gas Law is given by the equation PV=nRT, where P is the pressure, V is the volume, n is the number of moles, R is the universal gas constant, and T is the temperature in Kelvin.
02

Set Up the Equation for the Gas Constant R

To find the gas constant R, we rearrange the Ideal Gas Law to solve for R: R=PV/nT.
03

Substitute Known Values

Substitute the known values into the equation. P is 1 atm, V is 22.414 L, n is 1 mole, and T is 273 K.
04

Calculate the Gas Constant, R

Perform the calculation to find R. R=(1 atm)(22.414 L)/(1 mole)(273 K)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Universal Gas Constant
The universal gas constant, denoted as 'R', is a fundamental parameter in thermodynamics that appears in the ideal gas law. It's called 'universal' because it has the same value for all ideal gases, irrespective of their chemical identity or properties. This constant is crucial because it relates the energy scale to the gas scale when dealing with molecular gases.

R's value is determined through experimental measurements. To remember the significance of 'R', think of it as a conversion factor that balances the gas equation. It ensures that when we measure pressure (P), volume (V), and temperature (T) in their respective SI units, we attain consistent, reliable results in chemical calculations involving gases.
Gas Constant Calculation
To calculate the gas constant 'R', we must refer to a known set of conditions for a gas. A common approach is to use standard temperature and pressure conditions, where the volume of one mole of an ideal gas is known. This volume is about 22.414 liters at 0°C (273.15 K) and 1 atmosphere of pressure.

The calculation uses the Ideal Gas Law, rearranged to solve for R: \( R = \frac{PV}{nT} \). We substitute the measured values into this equation. With these standardized conditions (P=1 atm, V=22.414 L, n=1 mole, T=273 K), we can solve for R. The calculated R is consistent and reproducible, allowing chemists and physicists to carry out reliable gas-related calculations.
PV=nRT Equation
The Ideal Gas Law is encapsulated in the formula \(PV=nRT\), a cornerstone in the study of thermodynamics and chemistry. Each variable represents a physical property of a gas:
  • \(P\) stands for pressure, the force exerted by the gas per unit area.
  • \(V\) denotes volume, the space occupied by the gas.
  • \(n\) represents the number of moles, a measure of the amount of substance.
  • \(R\) is the already discussed universal gas constant.
  • \(T\) is the temperature, measured in Kelvin.
The equation states that the product of pressure and volume of a fixed amount of an ideal gas is directly proportional to its temperature. This relationship is vital for explaining how changes in temperature affect gas pressure and volume, which in turn is crucial for various applications, from industrial processes to predicting weather patterns.

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Most popular questions from this chapter

1\. An automobile air bag requires about \(62 \mathrm{~L}\) of nitrogen gas in order to inflate. The nitrogen gas is produced by the decomposition of sodium azide, according to the equation shown below $$ 2 \mathrm{NaN}_{3}(s) \rightarrow 2 \mathrm{Na}(s)+3 \mathrm{~N} 2(g) $$ What mass of sodium azide is necessary to produce the required volume of nitrogen at \(25^{\circ} \mathrm{C}\) and 1 atm? 2\. When \(\mathrm{Fe} 2 \mathrm{O}_{3}\) is heated in the presence of carbon, CO 2 gas is produced, according to the equation shown below. A sample of \(96.9\) grams of \(\mathrm{Fe} 2 \mathrm{O}_{3}\) is heated in the presence of excess carbon and the CO2 produced is collected and measured at 1 atm and \(453 \mathrm{~K}\). What volume of \(\mathrm{CO}_{2}\) will be observed? $$ 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~s})+3 \mathrm{C}(\mathrm{s}) \rightarrow 4 \mathrm{Fe}(\mathrm{s})+3 \mathrm{CO}_{2}(\mathrm{~g}) $$ 3\. The reaction of zinc and hydrochloric acid generates hydrogen gas, according to the equation shown below. An unknown quantity of zinc in a sample is observed to produce \(7.50 \mathrm{~L}\) of hydrogen gas at a temperature of \(404 \mathrm{~K}\) and a pressure of \(1.75 \mathrm{~atm} .\) How many moles of zinc were in the sample? $$ \mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(a q) \rightarrow \mathrm{ZnCl} 2(a q)+\mathrm{H} 2(g) $$

A sample of oxygen occupies \(17.5 \mathrm{~L}\) at \(0.75 \mathrm{~atm}\) and \(298 \mathrm{~K}\). The temperature is raised to \(303 \mathrm{~K}\) and the pressure is increased to \(0.987\) atm. What is the final volume of the sample?

1\. A sample of methane has a volume of \(17.5 \mathrm{~L}\) at \(100.0^{\circ} \mathrm{C}\) and \(1.72 \mathrm{~atm}\). How many moles of methane are in the sample? 2\. A \(0.0500 \mathrm{~L}\) sample of a gas has a pressure of \(745 \mathrm{~mm} \mathrm{Hg}\) at \(26.4^{\circ} \mathrm{C}\). The temperatureis now raised to \(404.4 \mathrm{~K}\) and the volume is allowed to expand until a final pressure of \(1.06\) atm is reached. What is the final volume of the gas? 3\. When \(128.9\) grams of cyclopropane \(\left(\mathrm{C}_{3} \mathrm{H}_{6}\right)\) are placed into an \(8.00 \mathrm{~L}\) cylinder at \(298 \mathrm{~K}\), the pressure is observed to be \(1.24\) atm. A piston in the cylinder is now adjusted so that the volume is now \(12.00 \mathrm{~L}\) and the pressure is \(0.88 \mathrm{~atm} .\) What is the final temperature of the gas?

1\. A container with a piston contains a sample of gas. Initially, the pressure in the container is exactly 1 atm, but the volume is unknown. The piston is adjusted so that the volume is \(0.155 \mathrm{~L}\) and the pressure is \(956 \mathrm{~mm}\) Hg; what was the initial volume? 2\. The pressure of \(12.5 \mathrm{~L}\) of a gas is \(0.82 \mathrm{~atm}\). If the pressure changes to \(1.32 \mathrm{~atm}\), what will the final volume be? A sample of helium gas has a pressure of \(860.0 \mathrm{~mm}\) Hg. This gas is transferred to a different container having a volume of \(25.0 \mathrm{~L}\); in this new container, the pressure is determined to be \(770.0 \mathrm{~mm}\) Hg. What was the initial volume of the gas?

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