A sample of oxygen occupies \(17.5 \mathrm{~L}\) at \(0.75 \mathrm{~atm}\) and \(298 \mathrm{~K}\). The temperature is raised to \(303 \mathrm{~K}\) and the pressure is increased to \(0.987\) atm. What is the final volume of the sample?

Short Answer

Expert verified
The final volume \( V2 \) of the gas is approximately 132.67 L.

Step by step solution

01

Understand the Given Data and Identify the Gas Law to Use

We are given the initial and final states of a gas and are asked to find the final volume. The appropriate gas law to use here is the Combined Gas Law, which is \( \frac{P1 \cdot V1}{T1} = \frac{P2 \cdot V2}{T2} \), where P is the pressure, V is the volume, and T is the temperature in Kelvin
02

List the Known Variables

The initial conditions are: \( P1 = 0.75 \mathrm{~atm} \), \( V1 = 17.5 \mathrm{~L} \), and \( T1 = 298 \mathrm{~K} \). The final conditions are: \( P2 = 0.987 \mathrm{~atm} \), and \( T2 = 303 \mathrm{~K} \). We are solving for the final volume, \( V2 \)
03

Rearrange the Combined Gas Law to Solve for the Final Volume \( V2 \)

Rearrange the equation to solve for \( V2 \): \( V2 = \frac{P1 \cdot V1 \cdot T2}{P2 \cdot T1} \)
04

Plug In the Known Values and Calculate \( V2 \)

Substitute the known values into the rearranged equation: \( V2 = \frac{0.75 \mathrm{~atm} \cdot 17.5 \mathrm{~L} \cdot 303 \mathrm{~K}}{0.987 \mathrm{~atm} \cdot 298 \mathrm{~K}} \) and calculate \( V2 \)
05

Perform the Calculation

Carrying out the calculation: \( V2 = \frac{0.75 \cdot 17.5 \cdot 303}{0.987 \cdot 298} = \frac{39,037.5}{294.246} = 132.67 \mathrm{~L} \) (rounded to two decimal places)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Laws
Understanding the behavior of gases is a fundamental part of chemistry and physics, and gas laws succinctly describe these behaviors. Gas laws help us predict the behavior of gases under varying conditions of pressure, volume, and temperature. The most commonly taught gas laws include Boyle's Law, Charles's Law, Avogadro's Law, Gay-Lussac's Law, and the Ideal Gas Law. Together, these laws provide a comprehensive description of gas behavior and are paramount when dealing with problems in chemistry. For instance, Boyle's Law states that the pressure and volume of a gas are inversely proportional at constant temperature, while Charles's Law asserts that the volume and temperature of a gas are directly proportional at constant pressure. The Combined Gas Law, which was used in the given exercise, integrates both Boyle's and Charles's Laws by showing the relationship between pressure, volume, and temperature when they are not held constant. Chemists and physicists use these laws to predict how gases will respond to changes in environmental conditions, which is crucial for everything from balloon inflation to predicting the behavior of the atmosphere.
Pressure-Volume-Temperature Relationship
The interconnection between pressure, volume, and temperature is essential in understanding gas behavior and is explained using the pressure-volume-temperature relationship. This relationship is embedded within the Combined Gas Law, which is expressed as \( \frac{P1 \cdot V1}{T1} = \frac{P2 \cdot V2}{T2} \). Here, P represents pressure, V signifies volume, and T indicates temperature.

Pressure is a measure of the force applied per unit area and is usually measured in atmospheres (atm) or Pascals (Pa). Volume is the amount of space that a gas occupies, typically measured in liters (L) or cubic meters (m³). Temperature must always be considered on an absolute scale, which is Kelvin in science, to provide accurate predictions. This relationship asserts that if a gas undergoes a change where no gas particles are added or removed, the initial state of the gas (P1, V1, T1) will be proportional to its final state (P2, V2, T2). In real-life applications, this law aids in calculating changes in one of the variables if the others are known, as demonstrated in the exercise provided.
Chemiosmotic Variables
While the term chemiosmotic variables may seem unfamiliar within the context of gas laws, it is related to the transport and energy conversion within cellular membranes found in the domain of biology. The concept of chemiosmosis refers to the movement of ions across a semipermeable membrane, down their electrochemical gradient. This process is crucial for the production of adenosine triphosphate (ATP), the energy currency of the cell. The key variables in chemiosmosis include the membrane potential, the pH gradient (or proton gradient), and the concentrations of different ions across the membrane. These variables are indeed environmental factors that affect the chemiosmotic process, similarly to how pressure, volume, and temperature influence gas behavior.

However, connecting chemiosmotic variables directly to the gas laws may be a bit of a stretch, as the principles governing chemiosmosis typically do not apply to the behavior of gases. Instructors should clarify that in the context of chemistry and physics, 'chemiosmotic' refers more broadly to variables affecting transport and energy, which diverges from the specific pressure-volume-temperature variables considered in the Combined Gas Law.

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Most popular questions from this chapter

1\. A sample of methane has a volume of \(17.5 \mathrm{~L}\) at \(100.0^{\circ} \mathrm{C}\) and \(1.72 \mathrm{~atm}\). How many moles of methane are in the sample? 2\. A \(0.0500 \mathrm{~L}\) sample of a gas has a pressure of \(745 \mathrm{~mm} \mathrm{Hg}\) at \(26.4^{\circ} \mathrm{C}\). The temperatureis now raised to \(404.4 \mathrm{~K}\) and the volume is allowed to expand until a final pressure of \(1.06\) atm is reached. What is the final volume of the gas? 3\. When \(128.9\) grams of cyclopropane \(\left(\mathrm{C}_{3} \mathrm{H}_{6}\right)\) are placed into an \(8.00 \mathrm{~L}\) cylinder at \(298 \mathrm{~K}\), the pressure is observed to be \(1.24\) atm. A piston in the cylinder is now adjusted so that the volume is now \(12.00 \mathrm{~L}\) and the pressure is \(0.88 \mathrm{~atm} .\) What is the final temperature of the gas?

1\. A container with a piston contains a sample of gas. Initially, the pressure in the container is exactly 1 atm, but the volume is unknown. The piston is adjusted so that the volume is \(0.155 \mathrm{~L}\) and the pressure is \(956 \mathrm{~mm}\) Hg; what was the initial volume? 2\. The pressure of \(12.5 \mathrm{~L}\) of a gas is \(0.82 \mathrm{~atm}\). If the pressure changes to \(1.32 \mathrm{~atm}\), what will the final volume be? A sample of helium gas has a pressure of \(860.0 \mathrm{~mm}\) Hg. This gas is transferred to a different container having a volume of \(25.0 \mathrm{~L}\); in this new container, the pressure is determined to be \(770.0 \mathrm{~mm}\) Hg. What was the initial volume of the gas?

The value of the proportionality constant \(R\), can be calculated from the fact that exactly one mole of a gas at exactly 1 atm and at 0 "C \((273 \mathrm{~K})\) has a volume of \(22.414 \mathrm{~L}\). Solution Substituting in the equation: $$ \begin{array}{c} P V=n R T \text { or } R=\frac{P V}{n T} \\ R=\frac{(1 a t m)(22.414 L)}{(1 m o l e)(273 K)}=0.082057 L \text { atm } m o l^{-1} K^{-1} \end{array} $$

1\. An automobile air bag requires about \(62 \mathrm{~L}\) of nitrogen gas in order to inflate. The nitrogen gas is produced by the decomposition of sodium azide, according to the equation shown below $$ 2 \mathrm{NaN}_{3}(s) \rightarrow 2 \mathrm{Na}(s)+3 \mathrm{~N} 2(g) $$ What mass of sodium azide is necessary to produce the required volume of nitrogen at \(25^{\circ} \mathrm{C}\) and 1 atm? 2\. When \(\mathrm{Fe} 2 \mathrm{O}_{3}\) is heated in the presence of carbon, CO 2 gas is produced, according to the equation shown below. A sample of \(96.9\) grams of \(\mathrm{Fe} 2 \mathrm{O}_{3}\) is heated in the presence of excess carbon and the CO2 produced is collected and measured at 1 atm and \(453 \mathrm{~K}\). What volume of \(\mathrm{CO}_{2}\) will be observed? $$ 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~s})+3 \mathrm{C}(\mathrm{s}) \rightarrow 4 \mathrm{Fe}(\mathrm{s})+3 \mathrm{CO}_{2}(\mathrm{~g}) $$ 3\. The reaction of zinc and hydrochloric acid generates hydrogen gas, according to the equation shown below. An unknown quantity of zinc in a sample is observed to produce \(7.50 \mathrm{~L}\) of hydrogen gas at a temperature of \(404 \mathrm{~K}\) and a pressure of \(1.75 \mathrm{~atm} .\) How many moles of zinc were in the sample? $$ \mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(a q) \rightarrow \mathrm{ZnCl} 2(a q)+\mathrm{H} 2(g) $$

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