1\. A sample of methane has a volume of \(17.5 \mathrm{~L}\) at \(100.0^{\circ} \mathrm{C}\) and \(1.72 \mathrm{~atm}\). How many moles of methane are in the sample? 2\. A \(0.0500 \mathrm{~L}\) sample of a gas has a pressure of \(745 \mathrm{~mm} \mathrm{Hg}\) at \(26.4^{\circ} \mathrm{C}\). The temperatureis now raised to \(404.4 \mathrm{~K}\) and the volume is allowed to expand until a final pressure of \(1.06\) atm is reached. What is the final volume of the gas? 3\. When \(128.9\) grams of cyclopropane \(\left(\mathrm{C}_{3} \mathrm{H}_{6}\right)\) are placed into an \(8.00 \mathrm{~L}\) cylinder at \(298 \mathrm{~K}\), the pressure is observed to be \(1.24\) atm. A piston in the cylinder is now adjusted so that the volume is now \(12.00 \mathrm{~L}\) and the pressure is \(0.88 \mathrm{~atm} .\) What is the final temperature of the gas?

Short Answer

Expert verified
1. The sample of methane contains approximately 0.730 moles. 2. The final volume of the gas when the temperature is raised to 404.4 K and the pressure is 1.06 atm is approximately 0.0409 L. 3. The final temperature of the cyclopropane gas when the volume changes to 12.00 L and the pressure is 0.88 atm is approximately 255.0 K.

Step by step solution

01

Use the Ideal Gas Law for Methane

The ideal gas law is expressed as PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature in Kelvin. Given that the volume V = 17.5 L, temperature T = (100.0 + 273.15) K = 373.15 K, and pressure P = 1.72 atm, we can solve for n (the number of moles of methane). R is 0.0821 L·atm/(mol·K).
02

Solve for the Number of Moles of Methane

Rearrange the ideal gas law to solve for n (n = PV / RT). Then plug in the values P = 1.72 atm, V = 17.5 L, R = 0.0821 L·atm/(mol·K), and T = 373.15 K. Calculate n.
03

Use Combined Gas Law For The Second Gas Sample

Use the combined gas law to find the final volume: P1V1/T1 = P2V2/T2. Given initial conditions P1 = 745 mmHg, V1 = 0.0500 L, T1 = (26.4 + 273.15) K, and final conditions P2 = 1.06 atm (1 atm = 760 mmHg), T2 = 404.4 K. First, convert P1 to atm and then solve for V2.
04

Calculate The Final Volume Of The Gas

Rearrange the combined gas law to solve for V2: V2 = P1V1T2 / (P2T1). Then plug in the converted P1, V1, T1, P2, and T2 to solve for V2.
05

Use Ideal Gas Law For Cyclopropane

Given the mass of cyclopropane, 128.9 g, we can calculate the number of moles using its molar mass (C3H6, molar mass = 3(12.01) + 6(1.008) g/mol). Then, we use the ideal gas law with the initial conditions to find the temperature and final conditions to find the new temperature (V2 and P2) after the volume change.
06

Determine The Final Temperature Of Cyclopropane

Rearrange the ideal gas law to solve for T2 (the final temperature): T2 = P2V2/nR. We already have calculated n from the initial conditions and mass. Now plug in P2 = 0.88 atm, V2 = 12.00 L, and the calculated value of n (n = mass / molar mass), along with R to solve for T2.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Methane Moles Calculation
The process of calculating the moles of methane involves the ideal gas law, which is expressed through the formula PV = nRT. In this case, to determine the number of moles (), we have the given volume (V) of methane gas, expressed in liters, the pressure (P) in atmospheres, and the temperature (T) converted into Kelvin by adding 273.15 to the given Celsius temperature. With the values for P, V, and T known, and the ideal gas constant (R) as 0.0821 L\(\cdot\)atm/(mol\(\cdot\)K), the moles of methane can be solved by rearranging the ideal gas equation to n = PV/RT.

By inserting the specific values into the rearranged formula, we find the exact number of moles present in the sample. It's important to ensure that all units match those required by the ideal gas equation, particularly temperature in Kelvin and pressure in atmospheres, to obtain the correct calculation. This conversion consistency is essential when applying the ideal gas law.
Gas Law Conversions
Conversions play a key role in applying gas laws effectively. In the case of the combined gas law, pressures may need to be converted between different units, such as from mmHg to atmospheres, because the gas law requires consistency in units. The conversion factor between mmHg and atm is that 1 atm equals 760 mmHg.

To apply the combined gas law correctly, it's also critical to convert temperatures to Kelvin. This is done by adding 273.15 to the Celsius temperature. Additionally, the volume and number of moles may need to be expressed in liters and moles respectively, consistent with the values for R, the ideal gas constant. Ensuring these conversions before applying the gas laws ensures accurate results and avoids common calculation errors.
Combined Gas Law Application
The combined gas law is a cornerstone when dealing with the three-state variables of a gas, which are pressure, volume, and temperature. It integrates Charles's Law, Boyle's Law, and Gay-Lussac's Law, and is represented as P1V1/T1 = P2V2/T2, where P is pressure, V is volume, T is temperature, and the subscripts 1 and 2 refer to the initial and final states of the gas, respectively.

In practice, the combined gas law allows us to calculate the unknown final state of a gas when the other conditions are known. For instance, if the initial pressure, volume, temperature, and final pressure and temperature are known, this law can be used to compute the final volume. It is essential to ensure all variables are in the correct units before calculation. Being a versatile tool, its application extends to a multitude of problems in thermodynamics and environmental science.
Cyclopropane Temperature Change
Analyzing temperature changes in gases such as cyclopropane involves the ideal gas equation once more. When the volume and pressure of a gas change, its temperature change can be determined, assuming we know the amount of gas in moles. In the case of cyclopropane, we first have to find the number of moles from its given mass and molar mass. After that, we can use the ideal gas law with the initial conditions to find the initial temperature and then apply it again with the final conditions to discover the new temperature after the change.

The temperature change can give us insights into the effects of pressure and volume changes on a gas within a confined space, such as a cylinder with a piston. This concept is pivotal in fields like anesthesia, where cyclopropane was historically used, demonstrating the practical implementations of the ideal gas law in real-world situations.

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Most popular questions from this chapter

A sample of oxygen occupies \(17.5 \mathrm{~L}\) at \(0.75 \mathrm{~atm}\) and \(298 \mathrm{~K}\). The temperature is raised to \(303 \mathrm{~K}\) and the pressure is increased to \(0.987\) atm. What is the final volume of the sample?

1\. An automobile air bag requires about \(62 \mathrm{~L}\) of nitrogen gas in order to inflate. The nitrogen gas is produced by the decomposition of sodium azide, according to the equation shown below $$ 2 \mathrm{NaN}_{3}(s) \rightarrow 2 \mathrm{Na}(s)+3 \mathrm{~N} 2(g) $$ What mass of sodium azide is necessary to produce the required volume of nitrogen at \(25^{\circ} \mathrm{C}\) and 1 atm? 2\. When \(\mathrm{Fe} 2 \mathrm{O}_{3}\) is heated in the presence of carbon, CO 2 gas is produced, according to the equation shown below. A sample of \(96.9\) grams of \(\mathrm{Fe} 2 \mathrm{O}_{3}\) is heated in the presence of excess carbon and the CO2 produced is collected and measured at 1 atm and \(453 \mathrm{~K}\). What volume of \(\mathrm{CO}_{2}\) will be observed? $$ 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(\mathrm{~s})+3 \mathrm{C}(\mathrm{s}) \rightarrow 4 \mathrm{Fe}(\mathrm{s})+3 \mathrm{CO}_{2}(\mathrm{~g}) $$ 3\. The reaction of zinc and hydrochloric acid generates hydrogen gas, according to the equation shown below. An unknown quantity of zinc in a sample is observed to produce \(7.50 \mathrm{~L}\) of hydrogen gas at a temperature of \(404 \mathrm{~K}\) and a pressure of \(1.75 \mathrm{~atm} .\) How many moles of zinc were in the sample? $$ \mathrm{Zn}(\mathrm{s})+2 \mathrm{HCl}(a q) \rightarrow \mathrm{ZnCl} 2(a q)+\mathrm{H} 2(g) $$

1\. A container with a piston contains a sample of gas. Initially, the pressure in the container is exactly 1 atm, but the volume is unknown. The piston is adjusted so that the volume is \(0.155 \mathrm{~L}\) and the pressure is \(956 \mathrm{~mm}\) Hg; what was the initial volume? 2\. The pressure of \(12.5 \mathrm{~L}\) of a gas is \(0.82 \mathrm{~atm}\). If the pressure changes to \(1.32 \mathrm{~atm}\), what will the final volume be? A sample of helium gas has a pressure of \(860.0 \mathrm{~mm}\) Hg. This gas is transferred to a different container having a volume of \(25.0 \mathrm{~L}\); in this new container, the pressure is determined to be \(770.0 \mathrm{~mm}\) Hg. What was the initial volume of the gas?

The value of the proportionality constant \(R\), can be calculated from the fact that exactly one mole of a gas at exactly 1 atm and at 0 "C \((273 \mathrm{~K})\) has a volume of \(22.414 \mathrm{~L}\). Solution Substituting in the equation: $$ \begin{array}{c} P V=n R T \text { or } R=\frac{P V}{n T} \\ R=\frac{(1 a t m)(22.414 L)}{(1 m o l e)(273 K)}=0.082057 L \text { atm } m o l^{-1} K^{-1} \end{array} $$

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