Chapter 10: Problem 101
Based on periodic trends, which one of these elements would you expect to be most easily oxidized: Ge, K, S, or N?
Short Answer
Expert verified
Potassium (K) is expected to be the most easily oxidized out of the choices given because it has the lowest ionization energy.
Step by step solution
01
Understanding Oxidation
Oxidation is the loss of electrons during a reaction by a molecule, atom, or ion. In the context of periodic trends, elements that lose electrons more easily are said to be more easily oxidized. Typically, elements with a lower ionization energy lose electrons more easily and are, therefore, more easily oxidized.
02
Considering Group Trends
Within any given group (column) in the periodic table, ionization energy decreases as you move down the group. This is because the valence electrons are further from the nucleus and more shielded by other electrons, making them easier to remove.
03
Considering Period Trends
Within any given period (row) in the periodic table, ionization energy generally increases as you move from left to right. This happens because the number of protons increases, which pulls the electrons closer to the nucleus, making them harder to remove.
04
Comparing the Given Elements
The elements given are Ge, K, S, and N. Among these, K (potassium) is the farthest to the left and is also in the fourth period, meaning it's lower on the table than the others. Based on these trends, K would have the lowest ionization energy and therefore would be the most easily oxidized.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation and Reduction in Chemistry
The process of oxidation involves an element losing electrons, and as a result, its oxidation state increases. In contrast, reduction is when an element gains electrons and experiences a decrease in its oxidation state. These processes are integral parts of redox reactions, which stand for reduction-oxidation reactions.
In an oxidation event, the 'oxidizing agent' gains the electrons that have been released, and is itself reduced. On the flip side, the 'reducing agent' that loses electrons and gets oxidized causes the reverse process to occur in another reacting species. Understanding these concepts is essential as we delve into why certain elements, like potassium (K) in your exercise, are more inclined to lose electrons whereas others hold onto their electrons more tenaciously.
Students should also note that the ease with which elements can be oxidized or reduced plays a crucial role in a myriad of chemical processes, including metabolic reactions in biology, energy storage in batteries, and the corrosion of metals.
In an oxidation event, the 'oxidizing agent' gains the electrons that have been released, and is itself reduced. On the flip side, the 'reducing agent' that loses electrons and gets oxidized causes the reverse process to occur in another reacting species. Understanding these concepts is essential as we delve into why certain elements, like potassium (K) in your exercise, are more inclined to lose electrons whereas others hold onto their electrons more tenaciously.
Students should also note that the ease with which elements can be oxidized or reduced plays a crucial role in a myriad of chemical processes, including metabolic reactions in biology, energy storage in batteries, and the corrosion of metals.
Ionization Energy
Ionization energy is the amount of energy required to remove an electron from an atom or ion in its gaseous state. It's a critical property that plays a pivotal role in predicting and understanding the chemical behavior of elements.
Lower ionization energy indicates that it's easier for an atom to lose an electron and undergo oxidation; this is typically seen in metals, especially alkali metals like potassium mentioned in the exercise. Conversely, high ionization energy suggests more difficulty in removing an electron, characteristic of nonmetals like nitrogen (N).
It's essential for students to grasp that ionization energy is influenced by factors such as the atomic radius, nuclear charge, and the electron configuration. These factors determine how tightly electrons are held by an element and therefore dictate the likelihood of an electron being released during chemical reactions.
Lower ionization energy indicates that it's easier for an atom to lose an electron and undergo oxidation; this is typically seen in metals, especially alkali metals like potassium mentioned in the exercise. Conversely, high ionization energy suggests more difficulty in removing an electron, characteristic of nonmetals like nitrogen (N).
It's essential for students to grasp that ionization energy is influenced by factors such as the atomic radius, nuclear charge, and the electron configuration. These factors determine how tightly electrons are held by an element and therefore dictate the likelihood of an electron being released during chemical reactions.
Periodic Table Group Trends
When navigating the periodic table, group trends refer to patterns that occur within columns of the table, also known as groups.
- As one moves down a group, the atomic radius generally increases due to the addition of energy levels. This causes the valence electrons to be further away from the nucleus, reducing the effective nuclear charge.
- Consequently, the ionization energy decreases down a group, making it easier for the atoms to lose their valence electrons and be oxidized, much like potassium (K) from the exercise.
- Electronegativity and electron affinity also exhibit similar trends, generally decreasing as you move down a group.
Periodic Table Period Trends
In addition to group trends, the periodic table also exhibits period trends, which are patterns that manifest across the rows, known as periods.
- Moving from left to right across a period, the nuclear charge increases due to an increase in the number of protons. This pulls the electrons closer to the nucleus, increasing the ionization energy.
- Therefore, elements on the left of a period generally have lower ionization energy and are more apt to be oxidized, unlike those on the right, which display higher ionization energy and are less likely to lose electrons.
- This trend explains why nonmetals, typically found on the right side of a period, are more commonly reduced rather than oxidized.