Consider the reaction: $$ 2 \mathrm{SO}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{SO}_{3}(\mathrm{~s}) $$ (a) If \(285.5 \mathrm{~mL}\) of \(\mathrm{SO}_{2}\) is allowed to react with \(158.9 \mathrm{~mL}\) of \(\mathrm{O}_{2}\) (both measured at \(\mathrm{STP}\) ), what are the limiting reactant and the theoretical yield of \(\mathrm{SO}_{3}\) ? (b) If \(2.805 \mathrm{~g}\) of \(\mathrm{SO}_{3}\) is collected (measured at \(\mathrm{STP}\) ), what is the percent yield for the reaction?

Short Answer

Expert verified
SO2 is the limiting reactant with a theoretical yield of 4.479 grams of SO3. The percent yield of the reaction is 62.61%.

Step by step solution

01

Convert volumes to moles

At STP, one mole of any ideal gas occupies 22.4 L (or 22400 mL). To find the number of moles of the gases, use the formula: \[ \text{number of moles} = \frac{\text{volume of gas at STP}}{22400 \text{ mL/mol}} \] Convert the volumes of \( \text{SO}_2 \) and \( \text{O}_2 \) to moles using this formula.
02

Determine the limiting reactant

Use the stoichiometry of the reaction to compare the mole ratios of the reactants to the mole ratio in the balanced equation. The reactant that gives the lesser number of moles of \( \text{SO}_3 \) is the limiting reactant.
03

Calculate the theoretical yield

The theoretical yield is the amount of product that could be formed from the limiting reactant, assuming full conversion. Multiply the moles of limiting reactant by the mole ratio between the limiting reactant and the product \( \text{SO}_3 \) from the balanced equation. Then convert the moles of \( \text{SO}_3 \) to grams using the molar mass of \( \text{SO}_3 \).
04

Determine the percent yield

Percent yield is calculated using the actual yield (the measured amount of product) and the theoretical yield. Use the equation: \[ \text{percent yield} = \left(\frac{\text{actual yield}}{\text{theoretical yield}}\right) \times 100\% \] Substitute the actual yield (2.805 g) and the theoretical yield from Step 3 into the equation to find the percent yield.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Limiting Reactant
In chemical reactions, reactants are often not used up in the same ratios they are provided. The limiting reactant is the substance that is completely consumed first, thus dictating the maximum amount of product that can be formed. It's like a baking scenario where the amount of cakes you can bake is limited by the ingredient that runs out first, no matter how much of the other ingredients you have left.

To identify the limiting reactant, first determine the number of moles of each reactant. Then, use the stoichiometric coefficients from the balanced equation to calculate which reactant would produce the least amount of product. This reactant is your limiting factor in the reaction. Understanding the concept of the limiting reactant is crucial in predicting the amounts of products formed and is a foundational skill in stoichiometry problems.
Theoretical Yield
The theoretical yield is the amount of product expected to be produced in a chemical reaction under perfect conditions, meaning no product is lost in the process, and all the limiting reactant is converted to the product. It's a bit like the 'ideal' goal a team aims for in a game, knowing that reaching it might not always be possible due to various limitations in real-life scenarios.

To determine the theoretical yield, you use the moles of the limiting reactant and the reaction’s stoichiometry. Multiply the number of moles of the limiting reactant by the stoichiometric factor from the balanced equation to find the number of moles of the product that could be formed. Then, convert the moles of the product to mass, considering its molar mass. Theoretical yield guides us in estimating how efficient a reaction has been by comparing it with the actual yield.
Percent Yield
Actual laboratory reactions often yield less product than theoretically predicted due to various factors such as incomplete reactions or loss of product. This is where percent yield comes into play, as it provides a measure of the efficiency of a reaction. The formula to calculate percent yield is simple yet informative:
\
\[ \text{percent yield} = \left(\frac{\text{actual yield}}{\text{theoretical yield}}\right) \times 100\% \]

In real life, the percent yield can be affected by many factors: reaction conditions, purity of reactants, or experimental error, to name a few. By comparing the actual yield (what was actually produced) to the theoretical yield (what ideally could have been produced), chemists can quantify the success of their reaction. It's a practical approach to gauge the reaction's practicality and optimize it further.
Mole Concept
The mole concept is a fundamental principle in chemistry that helps quantify matter. One mole is defined as exactly 6.02214076×10²³ elementary entities (this could be atoms, molecules, ions, etc.) and is the SI unit for amount of substance. This number is commonly known as Avogadro’s number.

In the context of stoichiometry, the mole concept is employed to convert between mass, particles, and volume (in the case of gases at Standard Temperature and Pressure, STP). For gases at STP, for instance, one mole occupies 22.4 liters. By using the mole concept and combining it with the molar mass (the mass of one mole of a substance), we can transition between the microscopic world of atoms and molecules and the macroscopic world we can measure. This is especially important for stoichiometry problems where balancing and understanding chemical equations is essential.

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