Chapter 11: Problem 120
A mixture containing \(4.33 \mathrm{~g}\) of \(\mathrm{CO}_{2}\) and \(3.11 \mathrm{~g}\) of \(\mathrm{CH}_{4}\) has a total pressure of \(1.09\) atm. What is the partial pressure of \(\mathrm{CO}_{2}\) in the mixture?
Short Answer
Step by step solution
Calculate the number of moles of each gas
Calculate the total number of moles of gas
Determine the mole fraction of \(\mathrm{CO}_{2}\)
Calculate the partial pressure of \(\mathrm{CO}_{2}\)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
It commonly comes into play when we are trying to calculate the amount of gas (as moles) given its volume, pressure, and temperature. For this calculation, however, knowing the molar mass of the gas enables us to find the number of moles directly from the mass using the simple rearrangement of the ideal gas law:
\[\begin{equation}n = \frac{mass}{molar~mass}\text{.}\text{\end{equation}\]}This can be done because we are looking at a fixed volume and temperature, leaving the number of moles as the only unknown.
Mole Fraction
To calculate the mole fraction, you take:
\[\begin{equation}mole~fraction = \frac{number~of~moles~of~a~component}{total~number~of~moles~of~all~components}\text{.}\text{\end{equation}\]}For our problem, we use the mole fraction to determine how much of the mixture's total pressure is due to \(\text{CO}_2\). Knowing the mole fraction of a component allows us to figure out its partial pressure, which is the pressure the component would exert if it were alone in the container at the same temperature.
Dalton's Law of Partial Pressures
Dalton's Law Equation
The partial pressure of each gas is proportional to its mole fraction:
\[\begin{equation}P_{total} = P_1 + P_2 + P_3 + \dots\text{,}\text{\end{equation}\]}\[\begin{equation}P_{individual} = mole~fraction \times P_{total}\text{,}\text{\end{equation}\]}where \(P_{total}\) is the total pressure of the gas mixture, and \(P_{individual}\) is the partial pressure of each gas. This concept is extremely useful when we want to determine the pressure contributed by a specific gas within a mixture, as in the exercise at hand.
Molar Mass
To find the molar mass, we sum up the atomic masses of all atoms in a molecule. For instance:
\[\begin{equation}Molar~mass~of~\text{CO}_2 = 12.01~g/mol~(C) + 2 \times 16.00~g/mol~(O) = 44.01~g/mol\text{.}\text{\end{equation}\]}Similarly, we can calculate the molar mass of any compound by using the atomic masses from the periodic table. Knowing the molar mass helps us convert between the mass of a substance and the number of moles, which is a necessary step in solving many chemistry problems, including the calculation of partial pressures in a gas mixture.