Chapter 11: Problem 84
Calculate the volume of each gas sample at STP. (a) \(21.2 \mathrm{~mol} \mathrm{~N}_{2} \mathrm{O}\) (b) \(0.215 \mathrm{~mol} \mathrm{CO}\) (c) \(0.364 \mathrm{~mol} \mathrm{CO}_{2}\) (d) \(8.6 \mathrm{~mol} \mathrm{C}_{2} \mathrm{H}_{6}\)
Short Answer
Expert verified
\( V_{N_2O} = 475.04 \text{ L}, V_{CO} = 4.816 \text{ L}, V_{CO_2} = 8.1536 \text{ L}, V_{C_2H_6} = 192.64 \text{ L} \)
Step by step solution
01
Identify the Molar Volume at STP
At standard temperature and pressure (STP), which is defined as 0°C (273.15 K) and 1 atm pressure, the molar volume of an ideal gas is approximately 22.4 liters per mole. Use this value for calculations.
02
Calculate the Volume of \(N_2O\) at STP
To calculate the volume of \(N_2O\) at STP, multiply the number of moles by the molar volume at STP: \[ V_{N_2O} = 21.2 \text{ mol} \times 22.4 \frac{\text{L}}{\text{mol}} \.\]
03
Calculate the Volume of \(CO\) at STP
To calculate the volume of \(CO\) at STP, multiply the number of moles by the molar volume at STP: \[ V_{CO} = 0.215 \text{ mol} \times 22.4 \frac{\text{L}}{\text{mol}} \.\]
04
Calculate the Volume of \(CO_2\) at STP
To calculate the volume of \(CO_2\) at STP, multiply the number of moles by the molar volume at STP: \[ V_{CO_2} = 0.364 \text{ mol} \times 22.4 \frac{\text{L}}{\text{mol}} \.\]
05
Calculate the Volume of \(C_2H_6\) at STP
To calculate the volume of \(C_2H_6\) at STP, multiply the number of moles by the molar volume at STP: \[ V_{C_2H_6} = 8.6 \text{ mol} \times 22.4 \frac{\text{L}}{\text{mol}} \.\]
06
Perform the Calculations
Use a calculator to perform the multiplication for each gas to find their respective volumes at STP. For example, for \(N_2O\): \[ V_{N_2O} = 21.2 \times 22.4 = 475.04 \text{ L} \]
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
STP conditions
Understanding Standard Temperature and Pressure (STP) conditions is pivotal for calculating gas volumes in chemistry. STP is defined as a temperature of 0°C (273.15 Kelvin) and a pressure of 1 atmosphere (atm). Under these conditions, gases have certain predictable behaviors that simplify calculations. Why is this important? When scientists and chemists talk about gases, they need a common baseline, and that's what STP provides - a reference point where the behavior of gases can be compared and predicted.
It's crucial for students to remember these conditions whenever dealing with problems involving gases, as they provide the framework for using the molar volume of an ideal gas, which has been experimentally found to be 22.4 liters per mole at STP. This simplifies many types of gas-related calculations and is an essential stepping stone before delving into more complex equations and concepts in gas laws.
It's crucial for students to remember these conditions whenever dealing with problems involving gases, as they provide the framework for using the molar volume of an ideal gas, which has been experimentally found to be 22.4 liters per mole at STP. This simplifies many types of gas-related calculations and is an essential stepping stone before delving into more complex equations and concepts in gas laws.
Molar Volume
Molar volume is the volume occupied by one mole of a substance, and at STP, for an ideal gas, this volume is the same for all gases: 22.4 Liters per mole. This uniformity arises because ideal gases are presumed to behave in a perfectly predictable manner under these conditions, where their particles are assumed not to attract or repel each other and take up a negligible volume themselves.
How to Use Molar Volume in Calculations
In practice, calculating the volume of a gas at STP involves multiplying the number of moles by 22.4 L/mol. For instance, in the provided exercise, the volume of each gas is found simply by applying this relationship. For educational emphasis, it's important to communicate to students that this value is an approximation based on empirical data and is used for solving problems under the assumption of ideal behavior.Ideal Gas Law
The Ideal Gas Law is a fundamental equation in chemistry that relates the pressure, volume, temperature, and amount of moles of a gas. It's represented as PV = nRT, where P is pressure, V is volume, n is moles, R is the universal gas constant, and T is temperature in Kelvin.
At STP, this equation can be simplified since we are given that P is 1 atm and T is 273.15 K. The value of R is a constant 0.0821 Latm/molK for these units. When students grasp this concept, they can interrelate various properties of gases. However, it's crucial to note that the ideal gas law assumes the gas under study behaves perfectly, which in reality, is an approximation. Not all gases will obey the law under all conditions, particularly under high pressures and low temperatures where gas particles interact more and the volume of the particles themselves cannot be neglected.
At STP, this equation can be simplified since we are given that P is 1 atm and T is 273.15 K. The value of R is a constant 0.0821 Latm/molK for these units. When students grasp this concept, they can interrelate various properties of gases. However, it's crucial to note that the ideal gas law assumes the gas under study behaves perfectly, which in reality, is an approximation. Not all gases will obey the law under all conditions, particularly under high pressures and low temperatures where gas particles interact more and the volume of the particles themselves cannot be neglected.
Stoichiometry
Stoichiometry is the field of chemistry that pertains to the quantitative relationships between the reactants and products in a chemical reaction. It is based on the conservation of mass where the total mass of reactants equals the total mass of products. It involves calculations based on the balanced chemical equation and often requires the use of conversion factors such as molar mass or molar volume.