It has been proposed that uranium be extracted from seawater to fuel nuclear power plants. If the concentration of uranium in seawater is \(3.2 \mu \mathrm{g} / \mathrm{L}\), how much seawater must be processed to generate one pound of uranium?

Short Answer

Expert verified
The volume of seawater required to extract one pound of uranium is given by \( \frac{1 \text{ pound}}{3.2 \times 10^{-7} \text{ pounds/L}} \), which is approximately 3,125,000 liters.

Step by step solution

01

Convert from micrograms to pounds

First, convert the concentration of uranium from micrograms to pounds since the question requires the final amount in pounds. There are 1,000,000 micrograms in a gram and 453,592.37 grams in a pound. Therefore, the amount of uranium in pounds per liter of seawater is given by the conversion factor: \( \frac{3.2 \text{ micrograms}}{1 \text{ L}} \times \frac{1 \text{ gram}}{1,000,000 \text{ micrograms}} \times \frac{1 \text{ pound}}{453,592.37 \text{ grams}} \).
02

Calculate the volume of seawater needed

Having the concentration in pounds per liter, calculate the volume of seawater needed to obtain one pound of uranium. To find the volume (\(V_\text{seawater}\)) that contains one pound of uranium, set up the equation with the concentration we found above and solve for \(V_\text{seawater}\): \(1 \text{ pound} = \text{concentration in pounds per liter} \times V_\text{seawater}\).
03

Perform the calculation

Now it's just a matter of performing the algebra to find the value of \(V_\text{seawater}\). Rearrange the previous equation to solve for \(V_\text{seawater}\) by dividing both sides of the equation by the concentration in pounds per liter. Use a calculator to complete the division and find the needed volume of seawater.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molarity and Solution Concentration
Understanding molarity and solution concentration is fundamental in chemistry, especially when dealing with the extraction of substances from solutions. For example, in the context of extracting uranium from seawater, the molarity indicates how much of this element is present in a given volume of water.

Molarity, often denoted by the symbol 'M,' is defined as the number of moles of a solute present in one liter of solution. However, in our case, the concentration of uranium is given in micrograms per liter, not moles. To find out how many liters of seawater we need to process for one pound of uranium, the concentration must first be understood in terms of weight per volume, then converted to a usable unit that will help us perform the necessary calculations.

In practical terms, solution concentration can help us measure how 'dense' a solute is within a solution, which is pivotal for industrial applications such as extracting materials from natural resources.
Conversion of Units in Chemistry
Conversion of units is a critical step in chemistry to ensure that equations and calculations use consistent measurements. In the process of calculating the volume of seawater needed to extract one pound of uranium, we initially encounter units in micrograms per liter, but our goal is to measure in pounds.

To convert micrograms to pounds, we require the knowledge of how these units relate to each other: one pound is equivalent to 453,592.37 grams and one gram equals 1,000,000 micrograms. By using the factor-label method, which involves a series of conversion factors set up as fractions, we can systematically cancel out the units until we arrive at the desired unit, thus ensuring accuracy in our measurements.

Mastery of unit conversion empowers students and chemists to navigate between various scales and units, such as moving from microscopic levels (micrograms) to quotidian or industrial scales (pounds) seamlessly. This skill is critical in the real-world application of chemistry, beyond just academic exercises.
Stoichiometry Calculations
Stoichiometry calculations are the bread and butter of quantitative chemistry, enabling chemists to predict the outcomes of chemical reactions and to determine the quantities of reactants or products involved. In the context of uranium extraction, stoichiometry involves calculating the volume of seawater required to obtain a certain mass of uranium.

By setting up a properly balanced equation that incorporates the concentration of uranium, we apply stoichiometry principles to solve for the unknown quantity - in our case, the volume of seawater, denoted as \(V_\text{seawater}\). The stoichiometric relationship between the mass of the uranium and the volume of seawater is linear, leading to a straightforward calculation once all units are properly aligned.

The fundamental premise in stoichiometry is the conservation of mass, which in practical applications like this, guides the process: every pound of uranium extracted must have come from a calculable volume of seawater, following the concentration determined earlier in the unit conversion process.

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