Chapter 13: Problem 84
Describe how you would make \(500.0 \mathrm{~mL}\) of a \(0.200 \mathrm{M}\) \(\mathrm{NaOH}\) solution from a \(15.0 \mathrm{M}\) stock \(\mathrm{NaOH}\) solution.
Short Answer
Expert verified
To prepare 500.0 mL of a 0.200 M NaOH solution, pipette 6.67 mL of a 15.0 M stock NaOH solution into a 500 mL volumetric flask and dilute to the mark with distilled water.
Step by step solution
01
Calculating the volume of stock solution required
Use the dilution formula \( C_1V_1 = C_2V_2 \) where \( C_1 \) is the concentration of the stock solution, \( V_1 \) is the volume of stock solution needed, \( C_2 \) is the desired concentration, and \( V_2 \) is the final volume of the diluted solution. We rearrange the formula to solve for \( V_1 \) as follows: \( V_1 = \frac{C_2V_2}{C_1} \) .
02
Substituting known values
Substitute the known values into the rearranged formula: \( V_1 = \frac{0.200 M \times 500.0 mL}{15.0 M} \) .
03
Calculating the volume of the stock solution
Perform the calculation to find \( V_1 \): \( V_1 = \frac{0.200 \times 500.0}{15.0} = \frac{100.0}{15.0} = \frac{20}{3} \) mL or approximately \( 6.67 \) mL.
04
Preparing the dilute solution
Measure out approximately \( 6.67 \) mL of the \( 15.0 \) M stock \( NaOH \) solution using a pipette or a graduated cylinder. Transfer this volume to a \( 500 \) mL volumetric flask. Add distilled water to the flask until the bottom of the meniscus is at the \( 500 \) mL mark. Mix the solution thoroughly to ensure homogeneity.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Dilution Formula
The dilution formula is a simple yet powerful tool in chemistry, allowing scientists and students alike to prepare solutions of a desired concentration from a more concentrated stock solution. The key relationship given by the formula is expressed as:
\( C_1V_1 = C_2V_2 \).
Here, \(C_1\) represents the concentration of the original, more concentrated solution, while \(V_1\) is the volume of this stock solution that you need to use. Conversely, \(C_2\) is the concentration of the target, diluted solution, and \(V_2\) is its total volume. The trick in using this formula is in the rearrangement to solve for the unknown quantity, which usually is the volume of stock solution needed—\(V_1\). Through cross multiplication and division, you can isolate this value, leading to a straightforward equation:
\( V_1 = \frac{C_2V_2}{C_1} \).
\( C_1V_1 = C_2V_2 \).
Here, \(C_1\) represents the concentration of the original, more concentrated solution, while \(V_1\) is the volume of this stock solution that you need to use. Conversely, \(C_2\) is the concentration of the target, diluted solution, and \(V_2\) is its total volume. The trick in using this formula is in the rearrangement to solve for the unknown quantity, which usually is the volume of stock solution needed—\(V_1\). Through cross multiplication and division, you can isolate this value, leading to a straightforward equation:
\( V_1 = \frac{C_2V_2}{C_1} \).
Molarity
Molarity, denoted as M, is a unit of concentration in chemistry that specifies the number of moles of a solute per liter of solution. It is one of the most common units used to express concentration because it directly relates to the amount of substance and the volume of the solution, thereby linking stoichiometry with volume measurement.
\( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
This equation is essential when preparing solutions of precise concentrations, as well as in stoichiometric calculations which involve reactions in solution. Understanding molarity is especially important when working with reactions that take place in an aqueous medium, where reactions rates and equilibrium states are highly dependent on the concentration of the dissolved substances.
Calculating Molarity
To calculate molarity, you use the formula:\( \text{Molarity (M)} = \frac{\text{moles of solute}}{\text{volume of solution in liters}} \).
This equation is essential when preparing solutions of precise concentrations, as well as in stoichiometric calculations which involve reactions in solution. Understanding molarity is especially important when working with reactions that take place in an aqueous medium, where reactions rates and equilibrium states are highly dependent on the concentration of the dissolved substances.
Volume Calculation
Volume calculation is fundamental when preparing diluted solutions from concentrated stock solutions. The volume of the stock solution required, based on the dilution equation, must be accurately measured to achieve the intended molarity of the diluted solution.
Accurate Measurement Techniques
For optimal results, using precise instruments such as pipettes or volumetric flasks is necessary, which will ensure that the dilution process is as accurate as possible. Additionally, when precision is key, be mindful of the meniscus—the curve seen at the top of a liquid in response to its container. Measurements should always be taken from the bottom of the meniscus at eye level to maintain consistency and accuracy.Sodium Hydroxide Solution
Sodium hydroxide (OH) is a commonly used strong base in the laboratory. When working with \(NaOH\) solutions, it's important to recognize that the substance is highly reactive and caustic, requiring careful handling, proper PPE, and consideration of safety protocols.