Chapter 16: Problem 30
What is electrolysis? Why is it useful?
Short Answer
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 16: Problem 30
What is electrolysis? Why is it useful?
These are the key concepts you need to understand to accurately answer the question.
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Get started for freeWhat is the oxidation state of a free element? Of a monoatomic ion?
Assign an oxidation state to each element in each reaction and use the change in oxidation state to determine which element is being oxidized and which element is being reduced. (a) \(\mathrm{CH}_{4}(g)+2 \mathrm{H}_{2} \mathrm{~S}(g) \longrightarrow \mathrm{CS}_{2}(g)+4 \mathrm{H}_{2}(g)\) (b) \(2 \mathrm{H}_{2} \mathrm{~S}(g) \longrightarrow 2 \mathrm{H}_{2}(g)+\mathrm{S}_{2}(g)\) (c) \(\mathrm{C}_{6} \mathrm{H}_{12} \mathrm{O}_{6}(s)+6 \mathrm{O}_{2}(g) \longrightarrow 6 \mathrm{CO}_{2}(g)+6 \mathrm{H}_{2} \mathrm{O}(g)\) (d) \(\mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{Cl}_{2}(g) \longrightarrow \mathrm{C}_{2} \mathrm{H}_{4} \mathrm{Cl}_{2}(g)\)
Gold is electroplated at the cathode of an electrolysis cell by this half- reaction. $$ \mathrm{Au}^{3+}(a q)+3 \mathrm{e}^{-} \longrightarrow \mathrm{Au}(s) $$ How many moles of electrons are required to electroplate \(1.40 \mathrm{~g}\) of Au?
For each reaction, identify the substance being oxidized and the substance being reduced. (a) \(\mathrm{Mg}\) (s) \(+\mathrm{Br}_{2}(g) \longrightarrow \mathrm{MgBr}_{2}\) (s) (b) \(2 \mathrm{Cr}^{3+}(a q)+3 \mathrm{Mn}(s) \longrightarrow 2 \mathrm{Cr}(s)+3 \mathrm{Mn}^{2+}(a q)\) (c) \(2 \mathrm{H}^{+}(a q)+\mathrm{Ni}(s) \longrightarrow \mathrm{H}_{2}(g)+\mathrm{Ni}^{2+}(a q)\)
Classify each half-reaction occurring in acidic aqueous solution as an oxidation or a reduction and balance the half-reaction. (a) \(\mathrm{MnO}_{4}^{-}(a q) \longrightarrow \mathrm{Mn}^{2+}(a q)\) (b) \(\mathrm{Pb}^{2+}(a q) \longrightarrow \mathrm{PbO}_{2}(s)\) (c) \(\mathrm{IO}_{3}^{-}(a q) \rightarrow \mathrm{I}_{2}(s)\) (d) \(\mathrm{SO}_{2}(g) \rightarrow \mathrm{SO}_{4}^{2-}(a q)\)
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