Write a nuclear equation for the beta decay of each nuclide. (a) Pb-214 (b) Bi-214 (c) Th-231 (d) Ac-227

Short Answer

Expert verified
Nuclear equations: (a) \(^{214}_{82}Pb \rightarrow ^{214}_{83}Bi + ^0_{-1}e \), (b) \(^{214}_{83}Bi \rightarrow ^{214}_{84}Po + ^0_{-1}e \), (c) \(^{231}_{90}Th \rightarrow ^{231}_{91}Pa + ^0_{-1}e \), (d) \(^{227}_{89}Ac \rightarrow ^{227}_{90}Th + ^0_{-1}e \).

Step by step solution

01

Writing the Nuclear Equation for Pb-214

In beta decay, a nuclide emits a beta particle, which is an electron. This can be represented by the symbol \( \beta^- \) or \( ^0_{-1}e \). During beta decay, a neutron is converted into a proton, so the atomic number increases by 1, but the atomic mass number remains the same. Thus, for Pb-214, the nuclear equation is \( ^{214}_{82}Pb \rightarrow ^{214}_{83}Bi + ^0_{-1}e \).
02

Writing the Nuclear Equation for Bi-214

Similarly to Pb-214, Bi-214 undergoes beta decay emitting a beta particle and transforming one neutron into a proton. Therefore, the nuclear equation for Bi-214 is \(^{214}_{83}Bi \rightarrow ^{214}_{84}Po + ^0_{-1}e \).
03

Writing the Nuclear Equation for Th-231

For Th-231, beta decay results in the emission of a beta particle and an increase in atomic number while the mass number stays the same. The nuclear equation for Th-231 is \(^{231}_{90}Th \rightarrow ^{231}_{91}Pa + ^0_{-1}e \).
04

Writing the Nuclear Equation for Ac-227

Ac-227 also undergoes beta decay to increase its atomic number by 1. The nuclear equation is \(^{227}_{89}Ac \rightarrow ^{227}_{90}Th + ^0_{-1}e \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nuclear Chemistry
Nuclear chemistry is a fascinating branch of chemistry that examines the processes and changes in the nucleus of atoms. Unlike chemical reactions that involve electrons and do not change the identity of an element, nuclear reactions involve changes in an atom's nucleus and can result in the transformation of one element into another. This is really the heart of nuclear chemistry — understanding how subatomic changes confer macroscopic alterations.

One of the fundamental processes in nuclear chemistry is radioactive decay, a natural phenomenon where unstable nuclei release energy in the form of radiation to reach a more stable state. During this process, different types of particles can be emitted, and these emissions include alpha particles, beta particles, and gamma rays. Each type of decay provides insights into the stability and characteristics of nuclei, and tracking these changes is essential for applications in medicine, power generation, and even archaeological dating.

In the given exercise, we're focusing on a specific type of decay called beta decay, which is a cornerstone topic in nuclear chemistry and crucial for understanding natural transmutation of elements.
Beta Particle Emission
Beta particle emission, one form of radioactive decay, involves the release of beta particles from a nucleus. A beta particle is essentially a high-speed electron (\beta^-) or positron (\beta+), but for the scope of our discussion, we'll focus on the electron, often represented as \( ^0_{-1}e \). The beta particle's charge and mass are crucial, as they are responsible for the changes occurring within the nucleus during decay.

When a nucleus undergoes beta decay, several things happen. The beta particle is ejected at high speed, carrying away energy from the nucleus. This ejection allows the nucleus to drop to a lower energy state, which is generally more stable. It's like a packed, overcrowded room where letting one person out (the beta particle) makes the room (the nucleus) a more comfortable place for everyone remaining.

Understanding beta decay is not only academically interesting but also practically relevant. In medical imaging, for example, the detection of beta particles helps in the precise location of cancers. In environmental science, beta particle emissions can be measured to monitor nuclear waste and pollution.
Neutron to Proton Conversion
Neutron to proton conversion is at the core of beta decay and is intrinsically linked to the conservation of charge principle. Here’s what happens during beta decay: a neutron (\( ^1_0n \) ), which is neutral, is transformed into a proton (\( ^1_1p \) ), which has a positive charge. Since charge must be conserved, the excess negative charge is carried away by the beta particle.

The mathematical representation of this conversion is deceptively simple, but behind it lies complex forces at play within the nucleus. Neutrons and protons are held together by the strong nuclear force, one of the four fundamental forces of nature. When a neutron is converted into a proton, it alters the balance of forces within the nucleus, which is why beta particles are emitted to maintain stability.

In a nuclear equation, we'll see that the atomic number (protons in the nucleus) of the element increases by one due to this neutron to proton conversion, but the mass number (total protons and neutrons) remains constant, as seen in the example of Pb-214 converting to Bi-214. This conversion is fundamental to the transformation of elements in the universe, including the formation of new elements within stars and during supernova explosions.

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