Chapter 17: Problem 73
One of the nuclides in spent nuclear fuel is U-234, an alpha emitter with a half-life of 2.44 * 105 years. If a spent fuel assembly contains 2.80 kg of U-234, how long does it take for the amount of U-234 to decay to less than 0.10 kg?
Short Answer
Expert verified
t is roughly 6.86 * 10^5 years.
Step by step solution
01
Understand the decay process and the related formula
Alpha decay is an exponential decay process characterized by a half-life, which is the time taken for half of the radioactive substance to decay. For this process, the number of remaining nuclei at time t can be given by the formula: \( N(t) = N_0 \times \left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}} \), where \( N(t) \) is the remaining amount, \( N_0 \) is the initial amount, \( t_{1/2} \) is the half-life, and \( t \) is the time elapsed.
02
Set up the decay equation with the given data
Insert the given values into the exponential decay equation to calculate how long it takes for the initial 2.80 kg of U-234 to decay to 0.10 kg: \( 0.10 = 2.80 \times \left(\frac{1}{2}\right)^{\frac{t}{2.44 \times 10^5}} \)
03
Solve the equation for time, t
First, divide both sides of the equation by 2.80 to isolate the exponential term: \( \frac{0.10}{2.80} = \left(\frac{1}{2}\right)^{\frac{t}{2.44 \times 10^5}}\). Take the natural logarithm of both sides to remove the base of the exponent, resulting in: \( \ln\left(\frac{0.10}{2.80}\right) = \ln\left(\left(\frac{1}{2}\right)^{\frac{t}{2.44 \times 10^5}}\right) \). This simplifies to: \( \ln\left(\frac{0.10}{2.80}\right) = \frac{t}{2.44 \times 10^5} \times \ln\left(\frac{1}{2}\right) \). Solve for \(t\) by multiplying both sides by \(2.44 \times 10^5\) and dividing by \(\ln\left(\frac{1}{2}\right)\), resulting in: \( t = \frac{\ln\left(\frac{0.10}{2.80}\right)}{\ln\left(\frac{1}{2}\right)} \times 2.44 \times 10^5 \).
04
Calculate the time, t, using a calculator
Using a calculator, evaluate the expression: \( t = \frac{\ln\left(\frac{0.10}{2.80}\right)}{\ln\left(\frac{1}{2}\right)} \times 2.44 \times 10^5 \) to find the time it takes for the U-234 to decay from 2.80 kg to 0.10 kg.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Exponential Decay Equation
Understanding the exponential decay equation is essential in grasping the behavior of radioactive isotopes, such as Uranium-234. This equation is beautifully succinct yet powerfully descriptive of the decay process, which decreases at a rate proportional to its current value. In mathematical terms, the formula is expressed as:
\[\begin{equation}N(t) = N_0 \times left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}\end{equation}\]
Here, \(N(t)\) represents the quantity of the substance after time \(t\), \(N_0\) is the initial quantity, \(t_{1/2}\) is the half-life of the substance, and the fraction represents the substance's reduction to half after each half-life period.
\[\begin{equation}N(t) = N_0 \times left(\frac{1}{2}\right)^{\frac{t}{t_{1/2}}}\end{equation}\]
Here, \(N(t)\) represents the quantity of the substance after time \(t\), \(N_0\) is the initial quantity, \(t_{1/2}\) is the half-life of the substance, and the fraction represents the substance's reduction to half after each half-life period.
Half-Life
Half-life, symbolized by \(t_{1/2}\), is a pivotal term in nuclear chemistry that measures the time required for half of a radioactive isotope to decay. It's an intrinsic property of each radioactive nuclide, unaffected by physical or chemical conditions. When we say that U-234 has a half-life of \(2.44 \times 10^5\) years, it means that after this duration, any sample of U-234 will have reduced to half its original mass.
Utilizing Half-Life in Calculations
When performing calculations, half-life offers a standard measure to predict the decay over time of radioactive isotopes. For educational exercises, visualizing this concept can improve comprehension—imagine a block of U-234 reducing by half every \(2.44 \times 10^5\) years, providing a concrete picture of the decay process.Alpha Decay
Alpha decay is a type of radioactive disintegration in which an atomic nucleus emits an alpha particle, consisting of two protons and two neutrons. This process leads to the decrease in atomic mass and atomic number. In our example, U-234 undergoes alpha decay, thus ejecting alpha particles and transforming into a different element with a lower atomic number and mass.
Characteristics of Alpha Decay
Alpha particles, being heavy and positively charged, have a limited ability to penetrate materials and can be stopped by a sheet of paper or even the skin. However, if ingested or inhaled, alpha emitters can be harmful. In equations, alpha decay is expressed as loss of an alpha particle (\(He^{2+}\)), leading to a new element and mass reduction.Nuclear Chemistry
Nuclear chemistry is the study of changes that occur within the nuclei of atoms. This field not only encompasses the radioactive decay of atoms, as we've seen with U-234, but also the principles underlying nuclear reactions, fission, and fusion processes. Understanding nuclear chemistry is fundamental to grasping energy generation in power plants, medical applications of radioactive isotopes, and the environmental impacts of radioactive waste.
Emerging from the principles of nuclear chemistry is the notion that nuclear reactions involve changes in an atom's nucleus, as opposed to chemical reactions that involve electrons but do not change an atom's nuclear composition. The principles of nuclear chemistry enable us to use mathematical models, like the exponential decay equation, to predict the behavior of radioactive materials over time, which is a crucial concept for fields ranging from environmental science to medicine.
Emerging from the principles of nuclear chemistry is the notion that nuclear reactions involve changes in an atom's nucleus, as opposed to chemical reactions that involve electrons but do not change an atom's nuclear composition. The principles of nuclear chemistry enable us to use mathematical models, like the exponential decay equation, to predict the behavior of radioactive materials over time, which is a crucial concept for fields ranging from environmental science to medicine.