Describe the differences between a molecular equation, a complete ionic equation, and net ionic equation. Give an example of each to illustrate the differences.

Short Answer

Expert verified
Molecular equations show all compounds as if they were molecular. Complete ionic equations split strong electrolytes into ions. Net ionic equations show only the species that participate in the reaction.

Step by step solution

01

Define Molecular Equation

A molecular equation is a chemical equation in which the reactants and products are written as if they were molecular substances, even if they exist in solution as ions.
02

Define Complete Ionic Equation

A complete ionic equation is one where all strong electrolytes are represented as ions, showing the dissociation that occurs in solution.
03

Define Net Ionic Equation

A net ionic equation shows only the ions and molecules that are directly involved in the chemical change, omitting spectator ions that do not participate in the reaction.
04

Provide Molecular Equation Example

Consider the reaction between aqueous solutions of sodium chloride and silver nitrate: \(\text{NaCl}(aq) + \text{AgNO}_3(aq) \rightarrow \text{NaNO}_3(aq) + \text{AgCl}(s)\).
05

Provide Complete Ionic Equation Example

The complete ionic equation for the reaction would be: \(\text{Na}^{+}(aq) + \text{Cl}^{-}(aq) + \text{Ag}^{+}(aq) + \text{NO}_3^{-}(aq) \rightarrow \text{Na}^{+}(aq) + \text{NO}_3^{-}(aq) + \text{AgCl}(s)\).
06

Provide Net Ionic Equation Example

The net ionic equation simplifies the above, showing only the ions that form the solid precipitate: \(\text{Ag}^{+}(aq) + \text{Cl}^{-}(aq) \rightarrow \text{AgCl}(s)\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Equations
Molecular equations are the initial descriptions most students encounter when they first learn about chemical reactions. As the name suggests, they show the reactants and products as complete, undissociated compounds, regardless of their actual state in solution. This type of equation gives us a clear and simplified overview of the reaction taking place, but it doesn't provide information about the ions that are really present in the solution when the reactants are soluble electrolytes.

For example, let's consider a reaction between hydrochloric acid (HCl) and sodium hydroxide (NaOH), which are both strong electrolytes and dissociate completely in aqueous solutions: \(\text{HCl}(aq) + \text{NaOH}(aq) \rightarrow \text{NaCl}(aq) + \text{H}_2\text{O}(l)\). In this molecular equation, each compound is written as if it were a molecule, even though in a solution, HCl and NaOH exist as ions.
Complete Ionic Equations
Students often grasp a better understanding of reactions when they move on to complete ionic equations, which show all the species in a solution as they actually exist: dissociated into ions. This form of the equation is more detailed than the molecular equation and represents the real situation in aqueous solutions where strong electrolytes are involved.

An example using the same reaction would show the dissociation of the acids and bases: \(\text{H}^{+}(aq) + \text{Cl}^{-}(aq) + \text{Na}^{+}(aq) + \text{OH}^{-}(aq) \rightarrow \text{Na}^{+}(aq) + \text{Cl}^{-}(aq) + \text{H}_2\text{O}(l)\). Here, you can see that each strong electrolyte is shown in its ionic form, as it would exist in an aqueous solution. Understanding this concept is crucial, as it sets the foundation for discerning which are the spectator ions and which ions actually contribute to the formation of the product in the reaction.
Chemical Reactions
The core of studying chemistry lies in understanding chemical reactions, which are processes where reactants transform into products. Chemical reactions involve the breaking and forming of chemical bonds, changes in chemical compositions, and can be represented through molecular, complete ionic, and net ionic equations.

Each type of equation has its purpose. While molecular equations provide a general overview, complete ionic equations offer a closer look into the species present in solution. Finally, net ionic equations present the essence of the chemical change by highlighting the ions that actively participate in the reaction. This progression from molecular to net ionic equations helps students visualize and understand chemical reactions not just as abstract concepts, but as real processes with tangible substances undergoing change – a fascinating journey from theory to the reality of chemistry in action.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What are the main indications that a chemical reaction has occurred?

What solution can you add to each cation mixture to precipitate one cation while keeping the other cation in solution? Write a net ionic equation for the precipitation reaction that occurs. (a) \(\mathrm{Sr}^{2+}(a q)\) and \(\mathrm{Hg}_{2}{ }^{2+}(a q)\) (b) \(\mathrm{NH}_{4}^{+}(a q)\) and \(\mathrm{Ca}^{2+}(a q)\) (c) \(\mathrm{Ba}^{2+}(a q)\) and \(\mathrm{Mg}^{2+}(a q)\) (d) \(\mathrm{Ag}^{+}(a q)\) and \(\mathrm{Zn}^{2+}(a q)\)

Balance each chemical equation. (a) \(\mathrm{Na}_{2} \mathrm{~S}(a q)+\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}(a q) \longrightarrow \mathrm{NaNO}_{3}(a q)+\mathrm{CuS}(s)\) (b) \(\mathrm{HCl}(a q)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)+\mathrm{Cl}_{2}(g)\) (c) \(\mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow \mathrm{H}_{2} \mathrm{O}(l)\) (d) \(\mathrm{FeS}(s)+\mathrm{HCl}(a q) \longrightarrow \mathrm{FeCl}_{2}(a q)+\mathrm{H}_{2} \mathrm{~S}(g)\)

Identify the spectator ions in the complete ionic equation. $$ \begin{aligned} \mathrm{Ba}^{2+}(a q)+2 \mathrm{I}^{-}(a q)+2 \mathrm{Na}^{+}(a q)+\mathrm{SO}_{4}^{2-}(a q) \longrightarrow & \longrightarrow \\ & \mathrm{BaSO}_{4}(s)+2 \mathrm{I}^{-}(a q)+2 \mathrm{Na}^{+}(a q) \end{aligned} $$

Billions of pounds of urea are produced annually for use as fertilizer. Balance the skeletal equation for the synthesis of urea. $$ \mathrm{NH}_{3}(g)+\mathrm{CO}_{2}(g) \longrightarrow \mathrm{CO}\left(\mathrm{NH}_{2}\right)_{2}(s)+\mathrm{H}_{2} \mathrm{O}(l) $$

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free