Chapter 8: Problem 50
For the reaction shown, calculate the theoretical yield of the product in moles for each of the initial quantities of reactants. $$ \mathrm{Ti}(s)+2 \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{TiCl}_{4}(s) $$ (a) \(2 \mathrm{~mol} \mathrm{Ti} ; 2 \mathrm{~mol} \mathrm{Cl}_{2}\) (b) \(5 \mathrm{~mol} \mathrm{Ti} ; 9 \mathrm{~mol} \mathrm{Cl}_{2}\) (c) \(0.483 \mathrm{~mol} \mathrm{Ti} ; 0.911 \mathrm{~mol} \mathrm{Cl}_{2}\) (d) \(12.4 \mathrm{~mol} \mathrm{Ti} ; 15.8 \mathrm{~mol} \mathrm{Cl}_{2}\)
Short Answer
Step by step solution
Write the balanced chemical equation
Identify the limiting reactant for each scenario
Calculate the theoretical yield for each reaction scenario
Scenario (a)
Scenario (b)
Scenario (c)
Scenario (d)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Stoichiometry
To perform stoichiometric calculations, you need to start with a balanced chemical equation. This equation tells you the molar ratio between reactants and products. For instance, in the given exercise, the balanced chemical equation is \(\mathrm{Ti}(s) + 2 \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{TiCl}_{4}(s)\), which signifies 1 mole of titanium (Ti) reacts with 2 moles of chlorine gas (\(\mathrm{Cl}_{2}\)) to produce 1 mole of titanium tetrachloride (\(\mathrm{TiCl}_{4}\)).
Using this ratio, we can calculate how much product can be formed from given amounts of reactants. This is an essential tool in chemistry because it helps predict the quantities needed for a reaction to take place fully or to find out how much product we can expect to produce.
Limiting Reactant
In the exercise provided, we determine the limiting reactant by comparing the mole ratio of the reactants to the ratios in the balanced equation. For instance, in scenario (a), we have 2 moles of titanium and 2 moles of chlorine gas. However, the titanium requires twice as much chlorine gas to react completely, making chlorine gas the limiting reactant, as only 1 mole of titanium can react with the 2 moles of chlorine gas present.
Identifying the limiting reactant is an essential step in stoichiometry. It not only determines the theoretical yield of a reaction but can also be utilized in industry to minimize waste and optimize resource usage. Students often struggle with this concept, so it's important to practice with various examples to become comfortable in finding the limiting reactant in chemical reactions.
Balanced Chemical Equations
The balanced chemical equation provided in the exercise, \(\mathrm{Ti}(s) + 2 \mathrm{Cl}_{2}(g) \longrightarrow \mathrm{TiCl}_{4}(s)\), shows a simple 1:2:1 ratio among titanium, chlorine gas, and titanium tetrachloride respectively. This tells us how many moles of each reactant are needed to produce a certain amount of product, and vice versa. To solve stoichiometric problems, the first critical step is always to write and confirm the balanced chemical equation. This step sets the stage for all subsequent calculations, such as identifying the limiting reactant and calculating theoretical yield.
Understanding how to balance chemical equations is an essential skill for any student studying chemistry. It not only is crucial for laboratory work but also helps to reinforce the understanding of atomic structure and conservation laws in chemical reactions.