Write orbital diagrams for the valence electrons and indicate the number of unpaired electrons for each element. (a) \(\mathrm{Br}\) (b) \(\mathrm{Kr}\) (c) \(\mathrm{Na}\) (d) In

Short Answer

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The number of unpaired electrons for each element: (a) Br - 1 unpaired electron, (b) Kr - 0 unpaired electrons, (c) Na - 1 unpaired electron, (d) In - 1 unpaired electron.

Step by step solution

01

Writing Orbital Diagram for Br

Bromine (Br) has an atomic number of 35, which means it has 35 electrons. The electron configuration for Br is [Ar]3d^104s^2 4p^5. The valence shell is the fourth shell (n=4), which includes the 4s and 4p subshells. The 4s subshell is fully occupied with 2 electrons, and the 4p subshell has 5 electrons. Therefore, the orbital diagram for the valence electrons of Br will have all two 4s electrons paired and three 4p orbitals half-filled with one electron each, and two 4p orbitals fully filled, resulting in 1 unpaired electron.
02

Writing Orbital Diagram for Kr

Krypton (Kr) has an atomic number of 36, meaning it has 36 electrons. The electron configuration for Kr is [Ar]3d^104s^2 4p^6. The valence shell for Kr is the fourth shell (n=4), which includes the 4s and 4p subshells. Both the 4s and the 4p subshells are fully occupied with 2 and 6 electrons, respectively. Thus, the orbital diagram for the valence electrons of Kr will have all orbitals fully filled, and as all electrons are paired, there are 0 unpaired electrons.
03

Writing Orbital Diagram for Na

Sodium (Na) has an atomic number of 11, which means it has 11 electrons. The electron configuration for Na is [Ne]3s^1. The valence shell is the third shell (n=3), which includes only the 3s subshell for Na. The 3s subshell has 1 electron. Therefore, the orbital diagram for the valence electrons of Na will have the 3s orbital half-filled with a single electron, resulting in 1 unpaired electron.
04

Writing Orbital Diagram for In

Indium (In) has an atomic number of 49, which means it has 49 electrons. The electron configuration for In is [Kr]4d^105s^2 5p^1. The valence shell is the fifth shell (n=5), which includes the 5s and 5p subshells. The 5s subshell is fully occupied with 2 electrons, and the 5p subshell has 1 electron. Thus, the orbital diagram for the valence electrons of In will have the 5s orbitals fully filled and one 5p orbital half-filled, resulting in 1 unpaired electron.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Valence Electrons
Valence electrons are the electrons situated in the outermost shell of an atom, which is also referred to as the valence shell. These electrons play a pivotal role in the chemical properties of elements, including how they bond with other atoms. The valence shell is defined by the highest energy level, represented by the principal quantum number, denoted as 'n'.

For instance, in the case of Bromine (Br), with an electron configuration of [Ar]3d104s24p5, its valence electrons would be located in the 4s and 4p orbitals because they are the outermost occupied shells. Knowing the distribution of these electrons helps us understand an element's reactivity, as they are the ones involved in forming chemical bonds.

It's important for students to grasp that while the inner electrons also contribute to the overall stability of atoms, it's the valence electrons that dictate most of the typical chemical reactions and are frequently represented in diagrams to illustrate bonding scenarios.
Unpaired Electrons
Unpaired electrons refer to electrons in an atom's orbitals that do not have a corresponding electron with opposite spin. These electrons are significant because they can contribute to the magnetic properties of an element and are often available for chemical bonding. In orbital diagrams, which are pictorial descriptions of the electrons in an atom's orbitals, unpaired electrons are denoted by single arrows.

As demonstrated in the example with Sodium (Na), with an electron configuration of [Ne]3s1, we observe that there is only one electron in the 3s orbital, making it unpaired. This unpaired electron is crucial for the chemical reactivity of Sodium, as it tends to lose this electron to achieve a more stable electron configuration, indicative of its propensity to participate in ionic bonding.

Understanding unpaired electrons is essential for predicting the behavior of atoms in different chemical contexts, especially in oxidation-reduction reactions where these electrons are transferred between atoms.
Electron Configuration
Electron configuration is the arrangement of electrons in an atom's orbitals. It is depicted using the principal energy levels and subshells, represented by quantum numbers and letters, respectively. The electron configuration can be thought of as a map that shows where the electrons reside in an atom. It is crucial for predicting an element's chemical behavior, as the arrangement of electrons influences the types of bonds that an element can form.

For each of the examples provided in the exercise, the electron configurations are distinct. Indium (In), for example, with an electron configuration of [Kr]4d105s25p1, indicates that the electrons occupy up to the fifth energy level. The 'd' and 's' orbitals are filled according to the Aufbau principle, which states that electrons fill orbitals starting with the lowest available energy states.

A solid comprehension of electron configuration is not only foundational for constructing orbital diagrams but also for understanding the periodic trends and the quantum mechanical nature of atoms. It serves as a baseline for more advanced topics in chemistry such as molecular orbital theory and spectroscopy.

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