List some sources of gamma rays.

Short Answer

Expert verified
Sources of gamma rays include decay of radioactive isotopes, celestial phenomena like supernovae, and man-made sources like nuclear reactors and medical equipment.

Step by step solution

01

Understanding Gamma Rays

Understand that gamma rays are high-frequency electromagnetic radiation, which arises from the decay of atomic nuclei as they undergo radioactive decay. Gamma rays are also produced in other high-energy processes.
02

Listing Natural Sources of Gamma Rays

Identify natural sources which include: radioactive decay of isotopes (e.g. cobalt-60, cesium-137), celestial bodies like neutron stars and black holes, and events such as supernovae and the interaction of cosmic rays with the Earth's atmosphere.
03

Listing Artificial Sources of Gamma Rays

List artificial sources, such as nuclear reactors, nuclear explosions, medical radiotherapy units, and industrial radiography equipment.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a natural process in which an unstable atomic nucleus loses energy by emitting radiation. This tends to happen in certain isotopes, which are variants of elements that have a different number of neutrons in their nuclei. Examples of such isotopes include cobalt-60 and cesium-137, which are known to emit gamma rays as they decay. The phenomenon can be imagined as an overcrowded room, where energy is released in the form of gamma rays as the 'extra' inhabitants (neutrons) leave to achieve a more stable state. The gamma rays emitted are packets of pure energy that travel at the speed of light and can penetrate most materials, giving them a wide range of applications but also making them a potential hazard if not managed carefully.

Understanding the half-life of an isotope—which is the time it takes for half of the radioactive substance to decay—is crucial in various fields, such as archaeology for carbon dating, and in medicine, where isotopes with shorter half-lives are used in certain diagnostic tests.
Celestial Bodies
The cosmos is a spectacular source of gamma rays, emitted by fascinating celestial bodies such as neutron stars, black holes, and during events like supernovae. Neutron stars are incredibly dense remnants of massive stars that have undergone a supernova explosion and collapsed into a compact state where protons and electrons have combined to form neutrons. A typical neutron star is so dense that a sugar-cube-sized amount of its material would weigh about a billion tons on Earth! The extreme magnetic fields and rapid rotation of neutron stars accelerate charged particles, which then emit gamma rays. Black holes, on the other hand, do not emit gamma rays directly but can be involved in processes that produce them. For example, material falling into a black hole heats up and accelerates, leading to gamma-ray emissions. Supernovae, the dramatic explosions signaling the death of a star, produce gamma rays as part of the immense energy release. And lastly, when cosmic rays collide with the Earth's atmosphere, they generate showers of secondary particles that can include gamma rays. These cosmic events not only fascinate astronomers but are also important in the study of high-energy physics and the universe's evolution.
Nuclear Reactors
Nuclear reactors are a prominent artificial source of gamma rays, which are produced during the nuclear fission process. Inside a reactor, heavy atomic nuclei, such as uranium or plutonium, are split into smaller fragments after absorbing a neutron. This splitting releases a tremendous amount of energy, manifesting partly as gamma radiation. The gamma rays play a crucial role in the energy production of the reactor, but they are also a significant safety concern. They need to be shielded by thick layers of concrete and other materials to protect the workers and the environment from harmful exposure. While most associated with power generation, nuclear reactors serve other purposes like research where gamma rays help in the discovery of new isotopes, and in the production of medical isotopes used for diagnosis and treatment. It's a balancing act of harnessing powerful energy while maintaining rigorous safety protocols.
Medical Radiotherapy
Medical radiotherapy is an essential tool in the treatment of cancer, utilizing gamma rays to target and destroy malignant cells. In this therapy, carefully controlled doses of gamma rays are directed at cancerous tissues. This high-energy radiation damages the DNA within the cancer cells, inhibiting their ability to reproduce and causing them to die. Healthy surrounding tissues can also be affected, which is why the precision of dosage and targeting is of utmost importance in radiotherapy. Radiotherapy may also be used in conjunction with surgery or chemotherapy in a multi-pronged approach to cancer treatment. Gamma rays for medical use can be obtained from radioactive isotopes, such as cobalt-60, or produced by machines like linear accelerators. The success of this treatment modality hinges on its careful application and a deep understanding of radiobiology—the field that combines the principles of biology with the physics of radiation.

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Most popular questions from this chapter

What is the difference between the ground state of an atom and an excited state of an atom?

Write orbital diagrams for the valence electrons and indicate the number of unpaired electrons for each element. (a) \(\mathrm{Br}\) (b) \(\mathrm{Kr}\) (c) \(\mathrm{Na}\) (d) In

When an electron makes a transition from the \(n=3\) to the \(n=2\) hydrogen atom Bohr orbit, the energy difference between these two orbits \(\left(3.0 \times 10^{-19} \mathrm{~J}\right)\) is emitted as a photon of light. The relationship between the energy of a photon and its wavelength is given by \(E=h c / \lambda\), where \(E\) is the energy of the photon in \(J, h\) is Planck's constant \(\left(6.626 \times 10^{-34} \mathrm{~J} \cdot \mathrm{s}\right)\), and \(c\) is the speed of light \(\left(3.00 \times 10^{8} \mathrm{~m} / \mathrm{s}\right)\). Find the wavelength of light emitted by hydrogen atoms when an electron makes this transition.

You learned in this chapter that ionization generally increases as you move from left to right across the periodic table. However, consider the following data, which shows the ionization energies of the period 2 and 3 elements: $$ \begin{array}{ccccc} \text { Group } & \begin{array}{c} \text { Period 2 } \\ \text { Elements } \end{array} & \begin{array}{c} \text { lonization } \\ \text { Energy } \\ \text { (kJ/mol) } \end{array} & \begin{array}{c} \text { Period 3 } \\ \text { Elements } \end{array} & \begin{array}{c} \text { Ionization } \\ \text { Energy } \\ \text { (kJ/mol) } \end{array} \\ \text { 1A } & \text { Li } & 520 & \text { Na } & 496 \\ \text { 2A } & \text { Be } & 899 & \text { Mg } & 738 \\ \text { 3A } & \text { B } & 801 & \text { Al } & 578 \\ \text { 4A } & \text { C } & 1086 & \text { Si } & 786 \\ \text { 5A } & \text { N } & 1402 & \text { P } & 1012 \\ \text { 6A } & \text { 0 } & 1314 & \text { S } & 1000 \\ \text { 7A } & \text { F } & 1681 & \text { Cl } & 1251 \\ \text { 8A } & \text { Ne } & 2081 & \text { Ar } & 1521 \\ \hline \end{array} $$ Notice that the increase is not uniform. In fact, ionization energy actually decreases a bit in going from elements in group \(2 \mathrm{~A}\) to \(3 \mathrm{~A}\) and then again from \(5 \mathrm{~A}\) to \(6 \mathrm{~A}\). Use what you know about electron configurations to explain why these dips in ionization energy exist.

Use the electron configurations of the alkaline earth metals to explain why they tend to form \(2+\) ions.

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