Chapter 9: Problem 80
Arrange the elements in order of increasing ionization energy: Ga, In, F, Si, N.
Short Answer
Expert verified
In < Ga < Si < N < F. The order is determined considering that ionization energy increases across a period and decreases down a group in the periodic table.
Step by step solution
01
Understand Ionization Energy
Ionization energy is the energy required to remove the most loosely bound electron from an atom in its gaseous state. It generally increases across a period from left to right due to increasing nuclear charge and decreases down a group due to increasing electron shell levels which cause a greater distance between the nucleus and the valence electrons, thus reducing nuclear attraction.
02
Locate Elements on the Periodic Table
Find the positions of Ga, In, F, Si, and N on the periodic table. Nitrogen (N) is in period 2, group 15; Phosphorus (P) is in period 2, group 16; Gallium (Ga) is in period 4, group 13; Indium (In) is in period 5, group 13; and Silicon (Si) is in period 3, group 14. Given that ionization energy decreases down groups and increases across periods, expect Ga and In to have lower ionization energies than N, F, and Si.
03
Compare Ionization Energy in the Same Group
Gallium (Ga) and Indium (In) are in the same group (group 13), with Ga being above In in the periodic table. Thus, Ga should have a higher (greater) ionization energy than In because Ga has a smaller atomic radius and the valence electrons are closer to the nucleus and more tightly bound.
04
Compare Ionization Energy across Periods
Nitrogen (N), Silicon (Si), and Fluorine (F) are in different periods and groups but we can compare their ionization energies as they are across the periods. F should have the highest ionization energy since it is furthest to the right, followed by N which is to the right of Si in period 2.
05
Arrange Elements in Order
The order of increasing ionization energy based on the above considerations is: In < Ga < Si < N < F. Indium has the lowest ionization energy, then Gallium, followed by Silicon, with Nitrogen having a higher ionization energy and Fluorine having the highest among the given elements.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
The Periodic Table and Ionization Energy
The periodic table is an invaluable tool in understanding various properties of elements, including ionization energy. Elements are arranged in order of increasing atomic number, laid out in a manner that groups elements with similar properties into columns and varying properties into rows or periods.
Ionization energy, which is the amount of energy needed to remove an electron from an atom, shows a noticeable trend within the periodic table. Across a period, ionization energy generally increases. This is due to the higher effective nuclear charge experienced by electrons as you move from left to right. The addition of protons in the nucleus as we go across a period means that electrons are more strongly attracted to the center, making them harder to remove.
In contrast, if you look at elements down a group, the ionization energy decreases even though the number of protons increases. This is because as we move down a group, new electron shells are added, increasing the distance between the nucleus and the outermost electrons, and thus reducing the effective nuclear charge felt by these electrons. Moreover, there's also an increase in electron shielding, with inner electrons repelling the outermost ones, making it easier to ionize atoms.
Ionization energy, which is the amount of energy needed to remove an electron from an atom, shows a noticeable trend within the periodic table. Across a period, ionization energy generally increases. This is due to the higher effective nuclear charge experienced by electrons as you move from left to right. The addition of protons in the nucleus as we go across a period means that electrons are more strongly attracted to the center, making them harder to remove.
In contrast, if you look at elements down a group, the ionization energy decreases even though the number of protons increases. This is because as we move down a group, new electron shells are added, increasing the distance between the nucleus and the outermost electrons, and thus reducing the effective nuclear charge felt by these electrons. Moreover, there's also an increase in electron shielding, with inner electrons repelling the outermost ones, making it easier to ionize atoms.
Atomic Radius and its Effect on Ionization Energy
The atomic radius is the distance from the nucleus of an atom to the boundary of its surrounding cloud of electrons. Understanding atomic radius helps explain trends in ionization energy. A smaller atomic radius generally indicates that electrons are located closer to the nucleus and more tightly held by the nucleus's positive charge. As such, a greater ionization energy is required to remove these electrons.
Conversely, a larger atomic radius means that valence electrons are further from the nucleus and can be removed with less energy. This effect is seen when comparing elements within a group; as atomic radius increases down a group, the ionization energy decreases. This can be attributed to the addition of electron shells, increasing the distance over which the nuclear charge must work to hold on to an electron.
It's worth mentioning that cations, which are positively charged ions, generally have a smaller radius compared to their neutral atoms due to the loss of the outermost electron(s), whereas anions, with added electrons, have a larger radius. These changes in radius affect the ionization energy nonetheless.
Conversely, a larger atomic radius means that valence electrons are further from the nucleus and can be removed with less energy. This effect is seen when comparing elements within a group; as atomic radius increases down a group, the ionization energy decreases. This can be attributed to the addition of electron shells, increasing the distance over which the nuclear charge must work to hold on to an electron.
It's worth mentioning that cations, which are positively charged ions, generally have a smaller radius compared to their neutral atoms due to the loss of the outermost electron(s), whereas anions, with added electrons, have a larger radius. These changes in radius affect the ionization energy nonetheless.
Nuclear Charge and its Relationship with Ionization Energy
Nuclear charge refers to the total charge of the nucleus due to the presence of protons, which is a contributor to an element's ionization energy. An important concept tied to nuclear charge is effective nuclear charge, which is the net positive charge experienced by electrons in the valence shell. It takes into account not only the total nuclear charge but also the shielding effect of electrons in inner shells.
The greater the effective nuclear charge, the tighter the nucleus holds onto its electrons, and as a result, higher is the ionization energy. In a period from left to right, for instance, the effective nuclear charge increases because additional protons in the nucleus attract the electrons more strongly. However, in a group from top to bottom, this effective charge decreases for the valence electrons due to increasing distance from the nucleus and the additional electron shielding from inner layers.
When we consider elements such as Ga and In from the exercise, despite both having a significant nuclear charge, the effective nuclear charge felt by the outer electrons in Ga is greater than in In. This is because Ga has fewer inner electron shells shielding the valence electrons from the nucleus, making its ionization energy relatively higher.
The greater the effective nuclear charge, the tighter the nucleus holds onto its electrons, and as a result, higher is the ionization energy. In a period from left to right, for instance, the effective nuclear charge increases because additional protons in the nucleus attract the electrons more strongly. However, in a group from top to bottom, this effective charge decreases for the valence electrons due to increasing distance from the nucleus and the additional electron shielding from inner layers.
When we consider elements such as Ga and In from the exercise, despite both having a significant nuclear charge, the effective nuclear charge felt by the outer electrons in Ga is greater than in In. This is because Ga has fewer inner electron shells shielding the valence electrons from the nucleus, making its ionization energy relatively higher.