Assign an oxidation state to each atom in the amino acid glycine:

Short Answer

Expert verified
The oxidation states for each atom in the amino acid glycine (H₂N-CH₂-COOH) are as follows: Nitrogen (N): -3, Hydrogen (H) in the amino group: +1, Carbon (C) in the methylene group: -2, Hydrogen (H) in the methylene group: +1, Carbon (C) in the carboxyl group: +3, Oxygen (O) in the double bond with carbon: -2, Oxygen (O) in the -OH group: -1, and Hydrogen (H) in the -OH group: +1.

Step by step solution

01

Identify the structure of glycine

Glycine has the molecular formula C2H5NO2, and its structure can be written as: H2N-CH2-COOH The molecule is composed of three main groups: - Amino group (NH2) - Methylene group (CH2) - Carboxyl group (COOH)
02

Apply general rules for assigning oxidation states

Let's apply the general rules for assigning oxidation states to each atom in glycine: 1. Oxidation state of hydrogen (H) in a compound is generally +1. 2. Oxidation state of oxygen (O) in a compound is generally -2. 3. The sum of oxidation states of all the atoms in a neutral molecule must be zero. Using these rules, we can assign oxidation states for each atom in glycine: - In the amino group (NH2): Each hydrogen will have an oxidation state of +1, and the nitrogen will have an oxidation state of -3 (since the sum of oxidation states in this group should be 0). - In the methylene group (CH2): Each hydrogen atom will have an oxidation state of +1, and the carbon will have an oxidation state of -2 (since the sum of oxidation states in this group should be 0). - In the carboxyl group (COOH): - The oxygen atom in the double bond with carbon will have an oxidation state of -2, - The other oxygen atom (in the -OH group) will have an oxidation state of -1 and the hydrogen atom will have an oxidation state of +1 (since the sum of oxidation states in the -OH group should be 0), - The carbon atom will have an oxidation state of +3 (since the sum of oxidation states in this group should be 0).
03

Verify the oxidation states

Now, let's verify that the sum of oxidation states in the entire molecule is indeed zero: (-3) + 2(+1) + (-2) + 2(+1) + (+3) + (-2) + (-1) + (+1) = 0 The sum of oxidation states in the glycine molecule is zero, which confirms that our assigned oxidation states are correct. To summarize, the oxidation states for each atom in glycine are: - Nitrogen (N): -3 - Hydrogen (H) in the amino group: +1 - Carbon (C) in the methylene group: -2 - Hydrogen (H) in the methylene group: +1 - Carbon (C) in the carboxyl group: +3 - Oxygen (O) in the double bond with carbon: -2 - Oxygen (O) in the -OH group: -1 - Hydrogen (H) in the -OH group: +1

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