Chapter 10: Problem 34
Draw a Lewis dot diagram for \(\mathrm{H}_{2} \mathrm{O}_{2}\) (hydrogen peroxide), and use the oxidation-state method of electron bookkeeping to determine how many electrons each atom should be assigned.
Short Answer
Expert verified
The Lewis dot structure for hydrogen peroxide (H₂O₂) is:
H
|
O - O
|
H
Using the oxidation-state method, we find that the oxidation states for the atoms are:
- Hydrogen atoms: +1 each
- Oxygen atoms: -1 each
Step by step solution
01
Draw the Lewis dot structure for hydrogen peroxide (H₂O₂)
First, we need to count the total number of valence electrons in the molecule. Hydrogen has 1 valence electron, and oxygen has 6 valence electrons. In H₂O₂, there are two hydrogen atoms and two oxygen atoms, so the total number of valence electrons is (2 × 1) + (2 × 6) = 14 electrons.
Next, we will arrange the atoms. The oxygen atoms will be the central atoms, with the hydrogen atoms bonded to either side. To form the bonds, we will share two electrons between each H and O atom.
Now, we will distribute the remaining electrons around the atoms to fulfill the octet rule for O atoms. In hydrogen peroxide, each O atom will have an octet of electrons since it has formed one single bond with an H atom, and one single bond with another O atom.
The Lewis dot structure for hydrogen peroxide will look like this:
H
|
O - O
|
H
02
Determine the oxidation state for each element
To do this, we use the oxidation-state method of electron bookkeeping. In this method, we assign the electrons in each bond to the more electronegative atom.
• In an O-H bond, oxygen is more electronegative, so each hydrogen atom loses its 1 valence electron to oxygen, giving them an oxidation state of +1.
• In an O-O bond, the atoms are the same, so they evenly share the 2 electrons. This means there is no change in oxidation states for these O atoms, so their oxidation state from the O-O bond is 0.
Now, let's determine the total oxidation state for each oxygen atom. Each oxygen atom received 1 electron from the hydrogen atom bonded to it, resulting in an oxidation state of -1. But there's also the O-O bond which gave no change in the oxidation state. So, the total oxidation state for each oxygen atom is -1 + 0 = -1.
Therefore, we have two hydrogen atoms with an oxidation state of +1 and two oxygen atoms with an oxidation state of -1.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation-State Method
The oxidation-state method is a systematic approach used in chemistry to keep track of electrons within compounds, especially when determining the electrons assigned to atoms in reactions. This method is based on the concept of oxidation states, which represent the degree of electron control or ownership an atom has in a bond relative to its pure elemental form.
Electronegativity plays a pivotal role here. It's a measure of how strongly an atom attracts electrons in a bond. In any covalent bond, the more electronegative atom is assigned more electrons, affecting its oxidation state. Oxidation states help us predict reactivity, understand redox reactions, and balance chemical equations.
To use the oxidation-state method effectively:
Electronegativity plays a pivotal role here. It's a measure of how strongly an atom attracts electrons in a bond. In any covalent bond, the more electronegative atom is assigned more electrons, affecting its oxidation state. Oxidation states help us predict reactivity, understand redox reactions, and balance chemical equations.
To use the oxidation-state method effectively:
- Assign all atoms their typical oxidation states depending on their positions in the periodic table and their bonds.
- In a bond, the more electronegative atom is often assigned the bonding electrons.
- In a bond between identical atoms, the electrons are divided equally.
Valence Electrons
Valence electrons play a leading role in chemical bonding and reactions. These are the electrons located in the outermost shell of an atom and are involved in forming bonds with other atoms.
An atom's chemical behavior is most deeply influenced by its valence electrons. Atoms strive to achieve a stable electronic configuration, often resembling the noble gas nearest to them in the periodic table. In the example of H₂O₂, hydrogen has 1 valence electron, and oxygen has 6, making up a total of 14 valence electrons available for bonding.
Understanding the count of valence electrons helps us to:
An atom's chemical behavior is most deeply influenced by its valence electrons. Atoms strive to achieve a stable electronic configuration, often resembling the noble gas nearest to them in the periodic table. In the example of H₂O₂, hydrogen has 1 valence electron, and oxygen has 6, making up a total of 14 valence electrons available for bonding.
Understanding the count of valence electrons helps us to:
- Predict how atoms will bond together.
- Apply the octet rule to determine the most stable arrangement of electrons.
- Formulate the correct Lewis dot structures.
Electron Bookkeeping
Electron bookkeeping is a crucial concept in managing the 'account' of electrons in compounds and during chemical reactions. It is particularly useful in complex redox reactions where electrons are transferred between species.
This bookkeeping involves:
This bookkeeping involves:
- Knowing the starting number of valence electrons for each atom.
- Understanding how bonds affect the distribution of these electrons.
- Applying rules such as electronegativity and the octet rule to determine how electrons are shared or transferred.
Octet Rule
The octet rule is a guiding principle in chemistry that postulates atoms are most stable when they have eight electrons in their outermost shell, similar to the electron configuration of a noble gas. Although there are exceptions, the octet rule applies to many main group elements and is a staple in drawing Lewis dot structures.
According to the octet rule:
According to the octet rule:
- Elements will typically form bonds to ensure they have a complete octet of electrons.
- Atoms can achieve a full octet through sharing (covalent bonds), losing (cation), or gaining (anion) electrons.