Chapter 10: Problem 5
Use the shortcut rules to assign oxidation states to all atoms. \(\mathrm{COCl}_{2}\) (oxygen and chlorine bonded to the central carbon) Answer: \(\mathrm{O}\) is \(-2\) (Rule 2). \(\mathrm{Cl}\) is \(-1\) (halide rule applies because \(\mathrm{Cl}\) is more electronegative than C). Therefore C is \(+4\) (the sum of the oxidation numbers for the \(\mathrm{O}\) and two \(\mathrm{Cl}^{\prime} \mathrm{s}\) is \(-4)\)
Short Answer
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Key Concepts
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