Chapter 10: Problem 55
Why can we always call an electron-transfer reaction a redox reaction?
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Chapter 10: Problem 55
Why can we always call an electron-transfer reaction a redox reaction?
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for freeConsider the perchlorate \(\left(\mathrm{ClO}_{4}^{-}\right)\) ion. (a) Assign oxidation states to all of the atoms in perchlorate. (b) Explain why the chlorine atom in perchlorate does not follow the halide rule. (c) Do you think perchlorate would be a powerful oxidizing agent or a powerful reducing agent? Explain. (d) Would it be possible to have an even higher oxidation state for the \(C 1\) atom in some other compound? Explain. (Hint: Chlorine is in group VIIA).
WorkPatch \(10.2\) had you assign oxidation states to the oxygen atoms in ozone. The answer was \(-1\) and 0 for the terminal (end) oxygen atoms and \(+1\) for the central oxygen atom. But now, a student claims the oxidation states are \(+1\) for the central oxygen atom and \(-1 / 2\) for the terminal oxygen atoms. He is also right. Explain why.
Ozone \(\left(\mathrm{O}_{3}\right)\) is a strong oxidizing agent. Explain why this is so.
Indicate whether each reaction is a redox reaction. If it is, which atom gets oxidized and which atom gets reduced? Consult the shortcut rules. \(\mathrm{P}_{4}+6 \mathrm{Br}_{2} \rightarrow 4 \mathrm{PBr}_{3}\) (Hint: \(\mathrm{Br}\) is more electronegative than P.)
What is an electron-transfer reaction?
What do you think about this solution?
We value your feedback to improve our textbook solutions.