Which of the following are redox reactions? (a) \(2 \mathrm{Na}+2 \mathrm{H}_{2} \mathrm{O} \rightarrow 2 \mathrm{NaOH}+\mathrm{H}_{2}\) (b) \(\mathrm{MgBr}_{2}+2 \mathrm{NaF} \rightarrow \mathrm{MgF}_{2}+2 \mathrm{NaBr}\) (c) \(2 \mathrm{CO}+\mathrm{O}_{2} \rightarrow 2 \mathrm{CO}_{2}\) (d) \(\mathrm{SO}_{2}+\mathrm{H}_{2} \mathrm{O} \rightarrow \mathrm{H}_{2} \mathrm{SO}_{3}\)

Short Answer

Expert verified
Reactions (a) and (c) are redox reactions, while reactions (b) and (d) are not.

Step by step solution

01

Identify the oxidation states of elements in each reaction.

(a) \(2\ \text{Na} + 2\ \text{H}_{2}\text{O}\ \rightarrow\ 2\ \text{NaOH} + \text{H}_{2}\) Oxidation states: \(\text{Na}\): before reaction is 0, after reaction is +1. \(\text{H}\): in \(\text{H}_{2}\text{O}\) is +1, in \(\text{NaOH}\) is +1, in \(\text{H}_{2}\) is 0. \(\text{O}\): in \(\text{H}_{2}\text{O}\) is -2, in \(\text{NaOH}\) is -2. (b) \(\text{MgBr}_{2} + 2\ \text{NaF}\ \rightarrow\ \text{MgF}_{2} + 2\ \text{NaBr}\) Oxidation states: \(\text{Mg}\): before reaction is +2, after reaction is +2. \(\text{Br}\): before reaction is -1, after reaction is -1. \(\text{Na}\): before reaction is +1, after reaction is +1. \(\text{F}\): before reaction is -1, after reaction is -1. (c) \(2\ \text{CO} + \text{O}_{2}\ \rightarrow\ 2\ \text{CO}_{2}\) Oxidation states: \(\text{C}\): in \(\text{CO}\) is +2, in \(\text{CO}_{2}\) is +4. \(\text{O}\): in \(\text{CO}\) is -2, in \(\text{O}_{2}\) is 0, in \(\text{CO}_{2}\) is -2. (d) \(1\ \text{SO}_{2} + \text{H}_{2}\text{O}\ \rightarrow\ \text{H}_{2}\text{SO}_{3}\) Oxidation states: \(\text{S}\): in \(\text{SO}_{2}\) is +4, in \(\text{H}_{2}\text{SO}_{3}\) is +4. \(\text{O}\): in \(\text{SO}_{2}\) is -2, in \(\text{H}_{2}\text{O}\) is -2, in \(\text{H}_{2}\text{SO}_{3}\) is -2. \(\text{H}\): in \(\text{H}_{2}\text{O}\) is +1, in \(\text{H}_{2}\text{SO}_{3}\) is +1.
02

Determine if the reactions are redox reactions.

We can now analyze the reactions based on their oxidation states: (a) There is a change in oxidation state for Na (from 0 to +1) and H (from +1 to 0). Since there's a transfer of electrons, this reaction is a redox reaction. (b) There is no change in oxidation states for any of the elements involved. Thus, this reaction is not a redox reaction. (c) There is a change in oxidation state for C (from +2 to +4) and O (from 0 to -2). Since there's a transfer of electrons, this reaction is a redox reaction. (d) There is no change in oxidation states for any of the elements involved. Thus, this reaction is not a redox reaction. In conclusion, reactions (a) and (c) are redox reactions, while reactions (b) and (d) are not.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free