What happens to the volume of a gas in a cylinder with a movable piston if: (a) The pressure is doubled while the temperature is held constant? (b) The temperature is doubled while the pressure is held constant? (c) The pressure and the temperature are both doubled? (The movable piston means the volume of the cylinder, and therefore of the gas, can change.)

Short Answer

Expert verified
(a) When the pressure is doubled while the temperature is held constant, the volume of the gas in the cylinder with a movable piston will be reduced to half of its initial volume: \(V_{new} = \frac{1}{2}V\). (b) When the temperature is doubled while the pressure is held constant, the volume of the gas in the cylinder with a movable piston will be doubled compared to its initial volume: \(V_{new} = 2V\). (c) When both the pressure and the temperature are doubled, the volume of the gas in the cylinder with a movable piston remains the same as its initial volume: \(V_{new} = V\).

Step by step solution

01

(a) Pressure is doubled, temperature constant

We are given that the pressure is doubled (\(P_{new} = 2P\)) while the temperature remains constant (\(T_{new} = T\)). We will use the initial and final conditions in the ideal gas equation to find the effect on volume. Initial Condition: \(PV = nRT\) Final Condition: \((2P)V_{new} = nR(T)\) Now, divide the final condition by the initial condition: \(\frac{(2P)V_{new}}{PV} = \frac{nRT}{nRT}\) Solving for \(V_{new}\): \(V_{new} = \frac{1}{2}V\) Thus, when the pressure is doubled while the temperature is held constant, the volume of the gas in the cylinder with a movable piston will be reduced to half of its initial volume.
02

(b) Temperature is doubled, pressure constant

Now we are given that the temperature is doubled (\(T_{new} = 2T\)) while the pressure remains constant (\(P_{new} = P\)). Again, use initial and final conditions in the ideal gas equation. Initial Condition: \(PV = nRT\) Final Condition: \(P(V_{new}) = nR(2T)\) Now, divide the final condition by the initial condition: \(\frac{P(V_{new})}{PV} = \frac{2nRT}{nRT}\) Solving for \(V_{new}\): \(V_{new} = 2V\) Thus, when the temperature is doubled while the pressure is held constant, the volume of the gas in the cylinder with a movable piston will be doubled compared to its initial volume.
03

(c) Pressure and temperature are doubled

Here, both pressure and temperature are doubled (\(P_{new} = 2P\) and \(T_{new} = 2T\)). Use the initial and final conditions in the ideal gas equation. Initial Condition: \(PV = nRT\) Final Condition: \((2P)V_{new} = nR(2T)\) Now, divide the final condition by the initial condition: \(\frac{(2P)V_{new}}{PV} = \frac{2nRT}{nRT}\) Solving for \(V_{new}\): \(V_{new} = V\) Thus, when both the pressure and the temperature are doubled, the volume of the gas in the cylinder with a movable piston remains the same as its initial volume.

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