Chapter 11: Problem 43
Rewrite the ideal gas law solving for \(T\). Also show how all units cancel to leave you with just units of temperature.
Chapter 11: Problem 43
Rewrite the ideal gas law solving for \(T\). Also show how all units cancel to leave you with just units of temperature.
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Get started for freeNormal atmospheric pressure will push a column of mercury up an evacuated glass tube (a barometer) to a height of \(76 \mathrm{~cm}(760 \mathrm{~mm} \mathrm{Hg})\), which we call one atmosphere. Suppose water were used as the liquid in a barometer instead of mercury. How high up would the atmosphere push a column of water in centimeters and in feet? Also, why would mercury give a more accurate indication of the atmospheric pressure then water? Some data you may need: Density of mercury, \(13.6 \mathrm{~g} / \mathrm{mL} ;\) Density of water, \(1.00 \mathrm{~g} / \mathrm{mL}\); Boiling point of mercury, \(357^{\circ} \mathrm{C}\); Boiling point of water, \(100^{\circ} \mathrm{C}\).
What must the Celsius temperature be if \(2.0\) moles of a gas in a 4.0-L steel container has a measured pressure of \(100 \mathrm{~atm} ?\)
What do we mean by inverse proportionality? By direct proportionality? Give an example of each using the way the pressure of a gas depends on something else.
Why are the results that are calculated using the ideal gas law not exactly equal to the "true" results obtained by an experimental measurement?
On an atomic basis, and given that the average kinetic energy of motion of molecules in the gas phase is given by \(\mathrm{KE}=3 R T / 2\), explain why the pressure of a gas doubles when its temperature in Kelvin is doubled. (Hint: Pressure is due to collisions of molecules on the container walls and the force of those collisions.)
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