Chapter 11: Problem 79
To what temperature must a gas initially at \(20.0^{\circ} \mathrm{C}\) be heated to double the volume and triple the pressure?
Short Answer
Expert verified
The gas must be heated to approximately \(1758.9\, K\) to double its volume and triple its pressure.
Step by step solution
01
Write down the given information
Initial Temperature (T₁) = 20.0°C = 293.15 K (converted to Kelvin by adding 273.15)
Initial Volume (V₁) = V (We assume the volume is V for easier calculation)
Initial Pressure (P₁) = P (We assume the pressure is P for easier calculation)
Final Volume (V₂) = 2V (Since volume is doubled)
Final Pressure (P₂) = 3P (Since pressure is tripled)
Final Temperature (T₂) = ? (This is what we want to find)
02
Apply the combined gas law equation
Combined gas law equation: \(PV/T = P_{1}V_{1}/T_{1} = P_{2}V_{2}/T_{2}\)
Substitute the given values and the assumed values into the equation:
\(P * V / 293.15 = (3P) * (2V) / T_{2}\)
03
Simplify the equation
Now, let's simplify the equation by canceling out the common terms P and V from both sides:
\(1 / 293.15 = 6 / T_{2}\)
04
Solve for the final temperature T₂
To get the final temperature T₂, we need to solve the equation:
\(T_{2} = 6 * 293.15\)
\(T_{2} = 1758.9\, K\)
So, the gas must be heated to 1758.9 K (approximately) to double its volume and triple its pressure.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Gas Temperature
Understanding gas temperature is crucial when studying how gases behave under various conditions. Temperature is a measure of the average kinetic energy of the particles in a substance. In the context of gases, as temperature increases, the particles move faster. This is important because faster-moving particles will collide with greater force and more often with the walls of their container, which generally increases the pressure if the volume is constant. Likewise, under constant pressure, increasing temperature can cause the gas to expand, hence increasing its volume.
This behavior is described by the fundamental gas laws, which include Charles's Law, stating that volume is directly proportional to temperature (when pressure is constant), and Gay-Lussac's Law, highlighting that pressure is directly proportional to temperature (when volume is constant). The exercise given effectively puts these principles to the test, asking us to determine the new temperature needed to double a gas's volume and triple its pressure.
This behavior is described by the fundamental gas laws, which include Charles's Law, stating that volume is directly proportional to temperature (when pressure is constant), and Gay-Lussac's Law, highlighting that pressure is directly proportional to temperature (when volume is constant). The exercise given effectively puts these principles to the test, asking us to determine the new temperature needed to double a gas's volume and triple its pressure.
Volume and Pressure Relationship
The intricate dance between volume and pressure in gases is governed by Boyle's Law, which tells us that volume is inversely proportional to pressure when temperature is held constant. This means if we increase the pressure exerted on a gas, its volume will decrease proportionally, and vice versa.
In the textbook exercise, we're asked to consider a scenario where both volume and pressure change. To navigate this, we look to the Combined Gas Law, which integrates Charles's, Gay-Lussac's, and Boyle's laws, allowing us to predict the state of a gas when multiple variables change. By doubling the volume and tripling the pressure, the Combined Gas Law helps us mathematically relate these changes to the final temperature, assuming we know the initial state of the gas.
In the textbook exercise, we're asked to consider a scenario where both volume and pressure change. To navigate this, we look to the Combined Gas Law, which integrates Charles's, Gay-Lussac's, and Boyle's laws, allowing us to predict the state of a gas when multiple variables change. By doubling the volume and tripling the pressure, the Combined Gas Law helps us mathematically relate these changes to the final temperature, assuming we know the initial state of the gas.
Kelvin Temperature Scale
The Kelvin temperature scale is pivotal in scientific calculations involving temperature, especially for gas laws. It is an absolute scale with 0 Kelvin representing absolute zero - the theoretical point where particles have minimum thermal motion.
The exercise's solution hinges on the use of the Kelvin scale, which is necessary because it provides a direct proportionality between volume, pressure, and temperature. Unlike the Celsius or Fahrenheit scales, the Kelvin scale ensures that a change in temperature by one Kelvin corresponds to the same change in energy, no matter what the starting temperature is. This is why we convert Celsius to Kelvin before using the Combined Gas Law equation by adding 273.15, resulting in a starting temperature of 293.15 K for the gas initially at 20.0°C.
The exercise's solution hinges on the use of the Kelvin scale, which is necessary because it provides a direct proportionality between volume, pressure, and temperature. Unlike the Celsius or Fahrenheit scales, the Kelvin scale ensures that a change in temperature by one Kelvin corresponds to the same change in energy, no matter what the starting temperature is. This is why we convert Celsius to Kelvin before using the Combined Gas Law equation by adding 273.15, resulting in a starting temperature of 293.15 K for the gas initially at 20.0°C.