Chapter 12: Problem 107
How many milliliters of a \(1.00 \mathrm{M}\) solution of \(\mathrm{NaCl}\) are required to obtain \(5.00 \mathrm{~g}\) of \(\mathrm{NaCl} ?\)
Short Answer
Expert verified
To obtain 5.00 g of NaCl, 85.6 mL of a 1.00 M solution of NaCl is required.
Step by step solution
01
Find the molar mass of NaCl
To find the molar mass of NaCl, we can add up the molar mass of sodium (Na) and chloride (Cl) since NaCl is composed of one atom of each. The molar mass for sodium is about 22.99 g/mol and the molar mass for chloride is about 35.45 g/mol.
Molar mass of NaCl = Molar mass of Na + Molar mass of Cl = \(22.99 \mathrm{~g/mol} + 35.45 \mathrm{~g/mol}\) = \(58.44 \mathrm{~g/mol}\)
02
Use the molarity formula to calculate the solution volume
Now, we'll use the molarity (M) formula to find the required volume of the solution.
M = (mass of solute) / (molar mass × volume of solution)
Rearrange the formula to solve for the volume of the solution:
Volume of solution = (mass of solute) / (M × molar mass)
In this case, M = 1.00 M, mass of solute = 5.00 g, and molar mass = 58.44 g/mol. Plug in the values to find the required volume of the solution.
Volume of solution = \(\frac{5.00 \mathrm{~g}}{1.00 \mathrm{~M} × 58.44 \mathrm{~g/mol}}\)
03
Calculate the volume of solution
Now, perform the calculation:
Volume of solution = \(\frac{5.00}{58.44}\)
Volume of solution = 0.0856 L
Convert the volume from liters to milliliters:
Volume of solution = 0.0856 L × (1000 mL/L) = 85.6 mL
04
State the answer
To obtain 5.00 g of NaCl, 85.6 mL of a 1.00 M solution of NaCl is required.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with Vaia!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Understanding Molar Mass
When it comes to chemical calculations, knowing the molar mass of a compound is crucial. Molar mass is defined as the mass of one mole of a substance and is expressed in grams per mole (g/mol). It's the sum of the atomic masses of all the atoms in a molecule. For example, in our exercise, the molar mass of sodium chloride (NaCl) is calculated by adding the atomic mass of sodium (Na), approximately 22.99 g/mol, to that of chlorine (Cl), approximately 35.45 g/mol, giving us 58.44 g/mol for NaCl.
This molar mass allows us to convert between the mass of a substance and the number of moles, serving as a bridge in many stoichiometric calculations. Remember, the molar mass is unique for each substance and can be found using the periodic table where each element's atomic mass is listed.
This molar mass allows us to convert between the mass of a substance and the number of moles, serving as a bridge in many stoichiometric calculations. Remember, the molar mass is unique for each substance and can be found using the periodic table where each element's atomic mass is listed.
- For compounds, simply add up the atomic mass of each element in the compound multiplied by the number of atoms of that element in one molecule of the compound.
Molarity Formula Demystified
Want to measure the concentration of a solution? Molarity is the term you're looking for. It's represented by 'M' and is defined as the number of moles of solute (the substance dissolved) per liter of solution. The molarity formula is a simple yet powerful tool in chemistry, given by:
\[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \]
But sometimes you need to find out how much volume is needed to obtain a certain amount of solute, as in our exercise. For that, we rearrange the formula to solve for volume:
\[ \text{Volume of solution} = \frac{\text{mass of solute}}{M \times \text{molar mass}} \]
It allows us to use the mass of a solute and its molar mass to find out the exact volume of a solution we need to prepare or use. It's vital to ensure the correct units are used—moles for the solute and liters for the solution volume. When you grasp this concept, solution preparation becomes a breeze.
\[ M = \frac{\text{moles of solute}}{\text{liters of solution}} \]
But sometimes you need to find out how much volume is needed to obtain a certain amount of solute, as in our exercise. For that, we rearrange the formula to solve for volume:
\[ \text{Volume of solution} = \frac{\text{mass of solute}}{M \times \text{molar mass}} \]
It allows us to use the mass of a solute and its molar mass to find out the exact volume of a solution we need to prepare or use. It's vital to ensure the correct units are used—moles for the solute and liters for the solution volume. When you grasp this concept, solution preparation becomes a breeze.
Preparing Solutions Accurately
In a laboratory setting, preparing solutions with accurate concentrations is an essential skill. The process involves measuring a specific amount of solute and dissolving it in a solvent to reach a desired volume, ensuring the proper molarity.
To achieve this, you start with calculating the amount of solute needed using the molarity formula. As seen in our example, we wanted to prepare a certain volume of a 1.00 M NaCl solution, so we calculated the grams of NaCl required. After calculating the mass of solute, we must dissolve it in a solvent (usually water) to reach the target volume of solution.
To achieve this, you start with calculating the amount of solute needed using the molarity formula. As seen in our example, we wanted to prepare a certain volume of a 1.00 M NaCl solution, so we calculated the grams of NaCl required. After calculating the mass of solute, we must dissolve it in a solvent (usually water) to reach the target volume of solution.
- Measure the solute mass precisely using a balance.
- Dissolve the solute in a smaller volume of solvent.
- Transfer this solution to a volumetric flask.
- Dilute with solvent to the final desired volume.
Applying Stoichiometry for Calculations
Stoichiometry is the section of chemistry that involves calculating the quantities of reactants and products involved in chemical reactions. It's based on the principle that matter is conserved during a reaction and therefore, can help in predicting the outcomes of reactions.
The concept becomes particularly useful when you want to calculate how much of a reactant you'll need to produce a certain amount of product, or vice versa. In the exercise given, we've used stoichiometric principles to determine the volume of a NaCl solution required to get a specific mass of NaCl. Here, stoichiometry connects the dots between the molar mass, the number of moles of a substance, and its mass in grams.
The concept becomes particularly useful when you want to calculate how much of a reactant you'll need to produce a certain amount of product, or vice versa. In the exercise given, we've used stoichiometric principles to determine the volume of a NaCl solution required to get a specific mass of NaCl. Here, stoichiometry connects the dots between the molar mass, the number of moles of a substance, and its mass in grams.
- Start with a balanced chemical equation.
- Use the molar mass to convert between mass and moles.
- Apply the mole ratio from the balanced equation to find moles of other substances involved.
- Finally, use molar mass or molarity as needed to find the final quantity.