Describe at the molecular level what is happening when solid iodine, \(\mathrm{I}_{2}(s)\), dissolves in carbon tetrachloride liquid, \(\operatorname{CCl}_{4}(l)\).

Short Answer

Expert verified
When solid iodine (I₂) dissolves in carbon tetrachloride (CCl₄), the nonpolar nature of both substances allows for weak London dispersion forces to form between their molecules. These forces overcome the van der Waals forces present in the crystalline structure of solid iodine, allowing I₂ molecules to diffuse into the CCl₄ liquid, resulting in a homogeneous solution.

Step by step solution

01

Identify the molecules involved

We have two substances: solid iodine (I₂) and carbon tetrachloride (CCl₄) liquid. Iodine is a diatomic molecule, meaning that it consists of two iodine atoms bonded together. Carbon tetrachloride is a molecular compound formed by a carbon atom (C) bonded to four chlorine atoms (Cl) in a tetrahedral shape.
02

Understand the initial state of solid iodine

Solid iodine has a crystalline structure where the individual I₂ molecules are held together by van der Waals forces (weak intermolecular forces). Each I₂ molecule consists of two iodine atoms covalently bonded together, forming a single I-I bond.
03

Consider the polarity of both substances

Since iodine (I₂) is a diatomic molecule, it is nonpolar in nature as there is no difference in electronegativity between the iodine atoms. Carbon tetrachloride (CCl₄) is also a nonpolar molecule due to its symmetrical structure that leads to equal distribution of electron density, even though the C-Cl bond itself is polar.
04

Understand the interactions between iodine and carbon tetrachloride molecules

As both iodine and carbon tetrachloride are nonpolar, there will be no formation of ion-dipole or dipole-dipole interactions between the molecules. Instead, the weak van der Waals forces, specifically London dispersion forces, will be responsible for holding I₂ and CCl₄ molecules together when mixed.
05

Describe the dissolving process of iodine in carbon tetrachloride

When solid iodine comes into contact with carbon tetrachloride, the London dispersion forces between the I₂ molecules and the CCl₄ molecules overcome the attractions within the I₂ solid lattice structure, allowing for individual I₂ molecules to diffuse into the CCl₄ liquid. The weak intermolecular forces between the I₂ and CCl₄ molecules allow I₂(s) to dissolve in CCl₄(l), resulting in a homogeneous solution.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free