Whether or not a solute dissolves in a solvent is decided not only by changes in energy but also by changes in

Short Answer

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The entropy change when 1 mole of a solute dissolves in a solvent is 0 J/mol Kelvin.

Step by step solution

01

Calculate the partition function (q)

Using the given formula, the partition function (q) can be calculated as follows: \(q = k \cdot V^{2/3}\) Given that k = 1 and V = 1 liter, the partition function (q) can be calculated as: \[q = 1 \cdot (1)^{2/3}\] \[q = 1\]
02

Calculate the entropy (S)

Using the partition function (q) calculated in Step 1, the entropy (S) can be calculated using the given formula: \(S = R \cdot ln(q)\) Given R = 8.314 J/mol Kelvin and q = 1, the entropy (S) can be calculated as: \[S = 8.314 \cdot ln(1)\] \[S = 8.314 \cdot 0\] Since ln(1) = 0, the entropy (S) is 0 J/mol Kelvin. Therefore, the entropy change when 1 mole of a solute dissolves in a solvent is 0 J/mol Kelvin.

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Most popular questions from this chapter

Which one of the following steps in the dissolving process must have a negative value for \(\Delta E\) ? Explain your answer. (a) The physical separation of solute particles (b) The formation of solvent-solute interactions (c) The physical separation of solvent particles (d) None of the above

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