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Chapter 12: Problem 20

Gasohol is a solution of gasoline and ethanol. Every liter of gasohol contains \(90.0 \mathrm{~mL}\) of ethanol dissolved in gasoline. Characterize the solute concentration by the appropriate percent composition. (Hint: Assume you have 1 L of gasohol solution.)

Short Answer

Expert verified
The solute concentration of ethanol in the gasohol solution is 9.0% by volume, calculated by dividing the volume of ethanol (90.0 mL) by the total volume (1000 mL) and then multiplying the result by 100.

Step by step solution

01

Convert ethanol volume to same unit as the total volume

The volume of ethanol is given in mL while the total volume is given in L. Convert the total volume to mL. 1 L = 1000 mL
02

Calculate the volume of gasoline

Find the volume of gasoline in the gasohol solution by subtracting the volume of ethanol from the total volume. Gasoline volume = Total volume - Ethanol volume Gasoline volume = 1000 mL - 90.0 mL = 910 mL
03

Calculate the percent composition of ethanol

To find the percent composition of ethanol in the gasohol solution, we will divide the volume of ethanol by the total volume and multiply the result by 100. Percent composition of ethanol = \( \frac{Ethanol \: volume}{Total \: volume} \times 100 \) Percent composition of ethanol = \( \frac{90.0\: mL}{1000\: mL} \times 100 \) Percent composition of ethanol = \( 0.09 \times 100 \) Percent composition of ethanol = 9.0% The solute concentration of ethanol in the gasohol solution is 9.0% by volume.

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