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Chapter 12: Problem 205

What is the volume in milliliters of \(0.0150 \mathrm{M}\) \(\mathrm{NaOH}\) solution required to neutralize \(50.0 \mathrm{~mL}\) of \(0.0100 \mathrm{M} \mathrm{H}_{2} \mathrm{SO}_{4}(a q) ?\)

Short Answer

Expert verified
66.7 mL of \(0.0150 \mathrm{M}\) NaOH solution is required to neutralize 50.0 mL of \(0.0100 \mathrm{M}\) H2SO4 solution.

Step by step solution

01

Write the balanced chemical equation

First, we need to write the balanced chemical equation for the neutralization reaction between sodium hydroxide (NaOH) and sulfuric acid (H2SO4). The balanced chemical equation is: 2 NaOH(aq) + H2SO4(aq) -> Na2SO4(aq) + 2 H2O(l)
02

Calculate moles of H2SO4

Next, we will calculate the moles of H2SO4 in the 50.0 mL solution. We can do this using the given concentration (0.0100 M) and the volume (50.0 mL). Remember to convert milliliters to liters: Moles of H2SO4 = (0.0100 moles/L) x (50.0 mL x (1 L / 1000 mL)) Moles of H2SO4 = 0.0005 moles
03

Determine moles of NaOH required to neutralize H2SO4

Now, we will calculate the moles of NaOH needed to neutralize the moles of H2SO4 we calculated in step 2. For this, we will use the stoichiometry of the balanced chemical equation (2 moles of NaOH required for 1 mole of H2SO4): Moles of NaOH = Moles of H2SO4 x (2 moles NaOH / 1 mole H2SO4) Moles of NaOH = 0.0005 moles x (2 moles NaOH / 1 mole H2SO4) Moles of NaOH = 0.0010 moles
04

Calculate the volume of NaOH solution required

Finally, we will find the volume of the 0.0150 M NaOH solution required to neutralize the H2SO4. We will use the moles of NaOH calculated in step 3 and the given concentration of the NaOH solution (0.0150 M). Remember to convert liters to milliliters: Volume of NaOH solution = (Moles of NaOH) / (Concentration of NaOH) Volume of NaOH solution = (0.0010 moles) / (0.0150 moles/L) Volume of NaOH solution = 0.0667 L Volume of NaOH solution = 0.0667 L x (1000 mL / 1 L) Volume of NaOH solution = 66.7 mL So, 66.7 mL of 0.0150 M NaOH solution is required to neutralize 50.0 mL of 0.0100 M H2SO4 solution.

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