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Chapter 12: Problem 23

What volume of \(0.350 \mathrm{M} \mathrm{CaF}_{2}\) solution is required to obtain \(0.00875\) mole of \(\mathrm{CaF}_{2} ?\)

Short Answer

Expert verified
The volume of the 0.350 M CaF₂ solution required to obtain 0.00875 moles of CaF₂ is 0.025 liters or 25 mL.

Step by step solution

01

Identify the given information

We are given: - Molarity (M) of CaF₂ solution: 0.350 M - Moles of CaF₂: 0.00875 Our goal is to find the volume of the solution (in liters) containing the given amount of CaF₂.
02

Use the molarity equation to find the volume

We'll use the formula: Molarity (M) = moles of solute / volume of solution (L) Rearrange the formula to solve for the volume: Volume of solution (L) = moles of solute / Molarity (M) Now, plug the given values into the equation: Volume of solution (L) = \( \frac{0.00875\text{ moles of CaF}_{2}}{0.350\text{ M}} \)
03

Calculate the volume of the solution

Divide the given values: Volume of solution (L) = \( \frac{0.00875}{0.350} \) = 0.025 L Therefore, 0.025 liters (25 mL) of the 0.350 M CaF₂ solution is required to obtain 0.00875 moles of CaF₂.

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