Write a general rate law for the reaction $$2 \mathrm{NO}+\mathrm{O}_{2} \rightarrow 2 \mathrm{NO}_{2}$$ using \(x\) and \(y\) as orders.

Short Answer

Expert verified
The general rate law for the reaction \(2 \mathrm{NO}+\mathrm{O}_{2} \rightarrow 2 \mathrm{NO}_{2}\) using \(x\) and \(y\) as orders is: \[\text{Rate} = k [\text{NO}]^x [\text{O}_{2}]^y \]

Step by step solution

01

Identify the reactants and their orders

In the reaction, the reactants are NO and O₂. The orders of the reactants are represented by x and y, respectively.
02

Write the general rate law

Using the general form of the rate law, substitute the reactants and their orders into the equation: Rate = k [NO]^x [O₂]^y where Rate is the reaction rate, k is the rate constant, [NO] and [O₂] are the concentrations of NO and O₂, and x and y are their respective orders. So, the general rate law for the given reaction is: \[\text{Rate} = k [\text{NO}]^x [\text{O}_{2}]^y \]

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