Chapter 14: Problem 59
What does a value of \(K_{\text {eq }}\) less than \(10^{-3}\) imply? Prove that your answer is correct by using the general expression \(K_{\text {eq }}=\) [Products \(] /[\) Reactants \(]\).
Chapter 14: Problem 59
What does a value of \(K_{\text {eq }}\) less than \(10^{-3}\) imply? Prove that your answer is correct by using the general expression \(K_{\text {eq }}=\) [Products \(] /[\) Reactants \(]\).
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Get started for free(a) Rewrite this reaction with the word heat in it: $$ 2 \mathrm{CO}(g)+\mathrm{O}_{2}(g) \rightleftarrows 2 \mathrm{CO}_{2}(g) \quad \Delta E=-563.5 \mathrm{~kJ} $$ (b) Which way does the reaction shift when the temperature is raised? Explain your answer.
What effect does a catalyst have on: (a) The position of equilibrium for a reaction? (b) The value of the equilibrium constant? (c) The ratio of \(k_{\mathrm{f}} / k_{\mathrm{r}} ?\) 14.86 What does a catalyst do to the time it takes for a reaction to reach equilibrium? Explain how it does this.
The amount of nitrogen dioxide formed by dissociation of dinitrogen tetroxide, \(\mathrm{N}_{2} \mathrm{O}_{4}(g) \rightleftarrows 2 \mathrm{NO}_{2}(g)\) increases as the temperature rises. (a) Is the reaction exothermic or endothermic? Explain how you know. (b) Does \(K_{\text {eq }}\) increase or decrease as the temperature rises?
What does a catalyst do to the time it takes for a reaction to reach equilibrium? Explain how it does this.
For the reaction \(4 \mathrm{NO}_{2}(g)+\mathrm{O}_{2}(g) \rightleftarrows 2 \mathrm{~N}_{2} \mathrm{O}_{5}(g)\) at \(25^{\circ} \mathrm{C}, K_{\mathrm{eq}}=0.150 .\) What is the equilibrium concentration of \(\mathrm{NO}_{2}(g)\) if \(\left[\mathrm{N}_{2} \mathrm{O}_{5}\right]=0.300 \mathrm{M}\) and \(\left[\mathrm{O}_{2}\right]=1.20 \mathrm{M} ?\)
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