What does a value of \(K_{\text {eq }}\) less than \(10^{-3}\) imply? Prove that your answer is correct by using the general expression \(K_{\text {eq }}=\) [Products \(] /[\) Reactants \(]\).

Short Answer

Expert verified
A value of \(K_{eq} < 10^{-3}\) implies that the equilibrium reaction favors the reactants, indicating that the forward reaction does not proceed extensively and only a small amount of products is formed. This is proven by the general expression \(K_{eq} = \frac{[Products]}{[Reactants]}\), where a small \(K_{eq}\) value indicates a greater concentration of reactants compared to the concentration of products.

Step by step solution

01

Understand the concept of equilibrium constant (\(K_{eq}\))

Equilibrium constant (\(K_{eq}\)) is a parameter that is used to quantify the extent of a chemical reaction at equilibrium. It is defined as the ratio of the concentration (or activities) of the products raised to their stoichiometric coefficients to the concentration (or activities) of the reactants raised to their stoichiometric coefficients. Mathematically, it can be represented as: \(K_{eq} = \frac{[Products]}{[Reactants]}\)
02

Analyze the behavior of \(K_{eq}\)

A large value of \(K_{eq}\) indicates that the products are favored at equilibrium, while a small value of \(K_{eq}\) indicates that the reactants are favored at equilibrium. When \(K_{eq} < 10^{-3}\), this implies that the equilibrium reaction favors the reactants and the forward reaction does not proceed extensively. In other words, only a small amount of products is formed.
03

Prove that a small \(K_{eq}\) implies that the reaction favors reactants

Let's assume a generic chemical equilibrium reaction: \(aA + bB \rightleftharpoons cC + dD\) where, A and B are the reactants, and C and D are the products, with their respective stoichiometric coefficients a, b, c, and d. The \(K_{eq}\) for this reaction will be: \(K_{\text {eq }}=\frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}}\) Now, let's assume that \(K_{eq} < 10^{-3}\). This means: \(K_{\text {eq }}=\frac{[C]^{c}[D]^{d}}{[A]^{a}[B]^{b}} < 10^{-3}\) Since \(10^{-3}\) is a very small value, this inequality indicates that the denominator (i.e., the concentration of reactants) is much greater than the numerator (i.e., the concentration of products). In other words: \([A]^{a}[B]^{b} > [C]^{c}[D]^{d}\) This clearly shows that when \(K_{eq} < 10^{-3}\), the reaction favors the reactants and there's only a small amount of products formed, proving our statement to be correct.

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