The equilibrium constant for the synthesis of methanol, $$ \mathrm{CO}(g)+2 \mathrm{H}_{2}(g) \rightleftarrows \mathrm{CH}_{3} \mathrm{OH}(g) $$ Methanol is \(4.3\) at \(250{ }^{\circ} \mathrm{C}\) and \(1.8\) at \(275^{\circ} \mathrm{C}\). (a) Does this reaction shift to the left or to the right when the reaction mixture is heated? Explain how you know. (b) Is this reaction endothermic or exothermic? Explain how you know. (c) Rewrite the equation for the reaction, including heat on the appropriate side.

Short Answer

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(a) The reaction shifts to the left when heated. (b) The reaction is endothermic. (c) The rewritten equation including heat is: \( \mathrm{CO}(g)+2 \mathrm{H}_{2}(g) + heat \rightleftarrows \mathrm{CH}_{3} \mathrm{OH}(g) \)

Step by step solution

01

1. Temperature effect on the reaction

When the reaction mixture is heated, the temperature of the system increases. In this case, we're given that increasing the temperature from 250°C to 275°C results in the equilibrium constant decreasing from 4.3 to 1.8.
02

2. Determining the direction of shift

Since the equilibrium constant decreases (from 4.3 to 1.8) when the temperature increases, we can conclude that the reaction shifts in the direction that absorbs heat. In other words, upon heating, the reaction will favor the reverse reaction, which is exothermic and releases heat. Therefore, the reaction shifts to the left.
03

3. Endothermic vs Exothermic

Given that the reaction shifts to the left when heated, this indicates that the forward reaction is endothermic, meaning it absorbs heat, and the reverse reaction is exothermic, meaning it releases heat.
04

4. Rewriting the equation with heat

As the forward reaction is endothermic, we can add heat to the left side of the reaction equation. The rewritten equation for the synthesis of methanol, including heat, is: \( \mathrm{CO}(g)+2 \mathrm{H}_{2}(g) + heat \rightleftarrows \mathrm{CH}_{3} \mathrm{OH}(g) \) To summarize: (a) The reaction shifts to the left when the reaction mixture is heated. (b) The reaction is endothermic. (c) The rewritten equation including heat is: \( \mathrm{CO}(g)+2 \mathrm{H}_{2}(g) + heat \rightleftarrows \mathrm{CH}_{3} \mathrm{OH}(g) \)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
In chemical reactions, chemical equilibrium is a state where the rate of the forward reaction equals the rate of the reverse reaction. As a result, the concentrations of the reactants and products remain constant over time, but not necessarily equal. A dynamic equilibrium exists because reactions continue to occur, but there is no net change in concentration.

For the synthesis of methanol:
\[\begin{equation} \mathrm{CO}(g) + 2 \mathrm{H}_2(g) \rightleftarrows \mathrm{CH}_3\mathrm{OH}(g) \end{equation}\], there is an equilibrium state reached where the formation rate of methanol and its decomposition occur at the same pace.
Le Chatelier's Principle
Le Chatelier's principle predicts how a system at equilibrium responds to changes in concentration, temperature, or pressure. If an external change is applied to a system at equilibrium, the system adjusts in such a way as to minimize that change. When the methanol reaction is heated, Le Chatelier's principle indicates that the system will respond by favoring the reaction that cools the system down. This is because increasing the temperature provides more energy to the reactants, shifting the equilibrium to favor the endothermic reaction that absorbs this excess heat.
Endothermic and Exothermic Reactions
The terms endothermic and exothermic describe the energy changes in a chemical reaction. Endothermic reactions absorb energy or heat from their surroundings, making the environment cooler. On the other hand, exothermic reactions release energy or heat, warming up their surroundings.

In the context of the methanol reaction:
\[\begin{equation} \mathrm{CO}(g) + 2 \mathrm{H}_2(g) + heat \rightleftarrows \mathrm{CH}_3\mathrm{OH}(g) \end{equation}\], the forward reaction is endothermic (absorbing heat), and the reverse reaction is exothermic (releasing heat). This understanding clarifies why the system shifts towards the reactants when the temperature is increased; it is a natural response to absorb excess thermal energy.
Temperature Effect on Reactions
The impact of temperature on chemical reactions is significant and predictable. As seen with the methanol synthesis, the equilibrium constant changes with temperature, reflecting the heat-dependency of the reaction. An increase in temperature causes molecules to move faster and collide more energetically, which can influence whether products or reactants are favored.

For endothermic reactions, such as the forward reaction in the synthesis of methanol, elevating the temperature shifts the equilibrium position to the right; the reverse is true for exothermic reactions. However, if the reaction is heated and the equilibrium constant decreases, this signifies that the favored direction is exothermic, since more of the products are being converted back to reactants to release heat and stabilize the temperature.

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Most popular questions from this chapter

What does a value of \(K_{\text {eq }}\) greater than \(10^{3}\) imply? Prove that your answer is correct by using the general expression \(K_{\mathrm{eq}}=[\) Products \(] /[\) Reactants \(]\).

\(K_{\text {eq }}=3.9 \times 10^{-11}\) for the dissolution of calcium fluoride in water: \(\mathrm{CaF}_{2}(s) \rightleftarrows \mathrm{Ca}^{2+}(a q)+2 \mathrm{~F}^{-}(a q)\) (a) What is another name for \(K_{\mathrm{eq}}\) for this reaction? (b) If the equilibrium calcium ion concentration in a saturated aqueous solution of calcium fluoride is \(3.3 \times 10^{-4} \mathrm{M}\), what is the equilibrium fluoride ion concentration? (c) Which is larger, the rate constant for the forward reaction or the rate constant for the reverse reaction? (d) Which is larger, \(E_{a}\) for the forward reaction or \(E_{\mathrm{a}}\) for the reverse reaction? (e) Which is larger, the rate of the forward reaction or the rate of the reverse reaction? (f) For lithium carbonate, \(K_{\mathrm{sp}}=0.0011\). Write the balanced chemical equation and the equilibrium expression for the dissolution of \(\mathrm{Li}_{2} \mathrm{CO}_{3}\) in water. (g) Which is more soluble in water, calcium fluoride or lithium carbonate?

Consider the reaction \(\mathrm{PCl}_{3}(g)+\mathrm{Cl}_{2}(g) \rightleftarrows \mathrm{PCl}_{5}(g)\) Use forward and reverse rate meters to represent the forward and reverse reaction rates for: (a) The initial equilibrium (b) Moments after you disturb the equilibrium by adding \(\mathrm{PCl}_{5}\) (c) The restored equilibrium (d) Which way did the reaction shift to get from the initial equilibrium, part (a), to the restored equilibrium, part (c)?

(a) How would you prepare a saturated aqueous solution of copper(I) iodide at \(25^{\circ} \mathrm{C}\) ? (b) What is the mass in milligrams of CuI in \(400.0 \mathrm{~mL}\) of the saturated solution? (Hint: Begin with a \(K_{\mathrm{sp}}\) value from Table 14.1.) (c) Suppose you add some CuI* to this saturated solution, where \(\mathrm{I}^{*}\) is a radioactive form of iodide ion. A student says, "Because the solution is already saturated, the added CuI* won't dissolve and there's no danger of getting any radioactive iodide ion in solution." What is wrong with his thinking?

Diamond and graphite are two forms of elemental carbon. Under the appropriate conditions they will be in equilibrium with each other: \(C_{\text {diamond }} \rightleftarrows C_{\text {graphite }}\) If graphite is subjected to very high pressure and temperature, it will convert into the diamond form. (a) Is the above equilibrium reaction exothermic or endothermic? Explain how you know. (b) Which form, graphite or diamond, has the higher density? (Hint: Think about what increasing the pressure of a gas does to its density. It works the same for the solid and liquid phases as well.)

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