Chapter 14: Problem 9
The equilibrium concentrations for the reaction \(\mathrm{CH}_{4}(g)+2 \mathrm{H}_{2} \mathrm{~S}(g) \rightleftarrows \mathrm{CS}_{2}(g)+4 \mathrm{H}_{2}(g)\) are \(\left[\mathrm{CS}_{2}\right]=6.10 \times 10^{-3} \mathrm{M},\left[\mathrm{H}_{2}\right]=1.17 \times 10^{-3} \mathrm{M},\left[\mathrm{CH}_{4}\right]=2.35 \times 10^{-3} \mathrm{M},\left[\mathrm{H}_{2} \mathrm{~S}\right]=2.93 \times\) \(10^{-3}\) M. Calculate \(K_{\mathrm{eq}}\) for this reaction.
Short Answer
Step by step solution
Key Concepts
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