It is possible to make two completely different buffers using the dihydrogen phosphate ion, \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) (a) In one buffer, \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) serves as the weak acid. What is the conjugate weak base? (b) Write the equations that show how the buffer in part (a) works when either \(\mathrm{H}_{3} \mathrm{O}^{+}\) or \(\mathrm{OH}^{-}\) is added. (c) In the other buffer, \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) serves as the weak base. What is the conjugate weak acid? (d) Write the equations that show how the buffer in part (c) works when either \(\mathrm{H}_{3} \mathrm{O}^{+}\) or \(\mathrm{OH}^{-}\) is added.

Short Answer

Expert verified
(a) The conjugate weak base of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) is \(\mathrm{HPO}_{4}^{2-}\). (b) Equations for buffer with \(\mathrm{H}_{3} \mathrm{O}^{+}\) and \(\mathrm{OH}^{-}\) added: 1. \(\mathrm{HPO}_{4}^{2-} + \mathrm{H}_{3} \mathrm{O}^{+} \rightarrow \mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}_{2} \mathrm{O}\) 2. \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{OH}^{-} \rightarrow \mathrm{HPO}_{4}^{2-} + \mathrm{H}_{2} \mathrm{O}\) (c) The conjugate weak acid of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) is \(\mathrm{H}_{3} \mathrm{PO}_{4}\). (d) Equations for buffer with \(\mathrm{H}_{3} \mathrm{O}^{+}\) and \(\mathrm{OH}^{-}\) added: 1. \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}_{3} \mathrm{O}^{+} \rightarrow \mathrm{H}_{3} \mathrm{PO}_{4} + \mathrm{H}_{2} \mathrm{O}\) 2. \(\mathrm{H}_{3} \mathrm{PO}_{4} + \mathrm{OH}^{-} \rightarrow \mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}_{2} \mathrm{O}\)

Step by step solution

01

(a) Identifying Conjugate Weak Base

The conjugate weak base of a weak acid is formed by removing a proton (H\(^{+}\)) from the acid. So, for \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\), the conjugate weak base will be: \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} \rightarrow \mathrm{H}^{+} + \mathrm{HPO}_{4}^{2-}\) The conjugate weak base is \(\mathrm{HPO}_{4}^{2-}\).
02

(b) Buffer Equations with H3O+ and OH- Added

When \(\mathrm{H}_{3} \mathrm{O}^{+}\) or \(\mathrm{OH}^{-}\) is added to a buffer containing \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) and \(\mathrm{HPO}_{4}^{2-}\), the following equations can be written: 1. When \(\mathrm{H}_{3} \mathrm{O}^{+}\) is added: \(\mathrm{HPO}_{4}^{2-} + \mathrm{H}_{3} \mathrm{O}^{+} \rightarrow \mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}_{2} \mathrm{O}\) 2. When \(\mathrm{OH}^{-}\) is added: \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{OH}^{-} \rightarrow \mathrm{HPO}_{4}^{2-} + \mathrm{H}_{2} \mathrm{O}\)
03

(c) Identifying Conjugate Weak Acid

The conjugate weak acid of a weak base is formed by adding a proton (H\(^{+}\)) to the base. So, for \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\), the conjugate weak acid will be: \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}^{+} \rightarrow \mathrm{H}_{3} \mathrm{PO}_{4}\) The conjugate weak acid is \(\mathrm{H}_{3} \mathrm{PO}_{4}\).
04

(d) Buffer Equations with H3O+ and OH- Added

When \(\mathrm{H}_{3} \mathrm{O}^{+}\) or \(\mathrm{OH}^{-}\) is added to a buffer containing \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) and \(\mathrm{H}_{3} \mathrm{PO}_{4}\), the following equations can be written: 1. When \(\mathrm{H}_{3} \mathrm{O}^{+}\) is added: \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}_{3} \mathrm{O}^{+} \rightarrow \mathrm{H}_{3} \mathrm{PO}_{4} + \mathrm{H}_{2} \mathrm{O}\) 2. When \(\mathrm{OH}^{-}\) is added: \(\mathrm{H}_{3} \mathrm{PO}_{4} + \mathrm{OH}^{-} \rightarrow \mathrm{H}_{2} \mathrm{PO}_{4}^{-} + \mathrm{H}_{2} \mathrm{O}\)

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