Name the acids: (a) \(\mathrm{HCl}\) (b) \(\mathrm{HNO}_{3}\) (c) \(\mathrm{H}_{2} \mathrm{SO}_{4}\) (d) HF (e) \(\mathrm{CH}_{3} \mathrm{COOH}\) (f) \(\mathrm{NH}_{1} \mathrm{Cl}\).

Short Answer

Expert verified
(a) Hydrochloric acid (b) Nitric acid (c) Sulfuric acid (d) Hydrofluoric acid (e) Acetic acid (f) NH\(_1\)Cl is not an acid, it could be either NH\(_4\)Cl (ammonium chloride) or NH\(_3\) (ammonia).

Step by step solution

01

(a) Naming HCl

HCl is a binary acid, made up of hydrogen (H) and chlorine (Cl). In hydracids, we use the prefix "hydro-" and the suffix "-ic" followed by the word "acid". So, HCl is called hydrochloric acid.
02

(b) Naming HNO\(_3\)

HNO\(_3\) is an oxyacid formed by hydrogen (H), nitrogen (N), and oxygen (O). Oxyacids are named with the suffix "-ic" followed by the word "acid" when the anion has more oxygen atoms, and the suffix "-ous" followed by "acid" when the anion has fewer oxygen atoms. In this case, HNO\(_3\) is named as nitric acid.
03

(c) Naming H\(_2\)SO\(_4\)

H\(_2\)SO\(_4\) is also an oxyacid, consisting of hydrogen (H), sulfur (S), and oxygen (O). Similar to HNO\(_3\), we name oxyacids by identifying the number of oxygen atoms. Since H\(_2\)SO\(_4\) has four oxygen atoms, it is named as sulfuric acid.
04

(d) Naming HF

HF is another hydracid formed by hydrogen (H) and fluorine (F). Following the same naming convention as HCl, we name HF as hydrofluoric acid.
05

(e) Naming CH\(_3\)COOH

CH\(_3\)COOH, also known as acetic acid, is a carboxylic acid. It's an organic compound containing a carboxyl group (\(\mathrm{COOH}\)) bonded to a methyl group (CH\(_3\)). The \(\mathrm{COOH}\) group gives this compound its acidic properties. This acid is a common component in vinegar and is well known as acetic acid.
06

(f) Naming NH\(_1\)Cl

NH\(_1\)Cl seems to be an error in the given exercise, as it is not an acid. An acid should have a hydrogen atom that can be donated as a proton. The correct formula could be either NH\(_4\)Cl, which is a salt (ammonium chloride), or NH\(_3\), which is a weak base (ammonia).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free