How many moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\) does it take to neutralize \(2.5\) moles of \(\mathrm{HNO}_{3}\) ?

Short Answer

Expert verified
It takes \(1.25\) moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\) to neutralize \(2.5\) moles of \(\mathrm{HNO}_{3}\).

Step by step solution

01

Write the balanced chemical equation for the reaction

First, we need to write the chemical equation for the neutralization reaction between \(\mathrm{Ba}(\mathrm{OH})_{2}\) and \(\mathrm{HNO}_{3}\), and then balance it: \[\mathrm{Ba}(\mathrm{OH})_{2} + 2\mathrm{HNO}_{3} \rightarrow \mathrm{Ba}(\mathrm{NO}_{3})_{2} + 2\mathrm{H}_{2}\mathrm{O}\]
02

Determine the mole ratio of the reactants

Now that we have the balanced chemical equation, we can determine the mole ratio of the reactants. In this case, it is \(1:2\), meaning that for every mole of \(\mathrm{Ba}(\mathrm{OH})_{2}\), \(2\) moles of \(\mathrm{HNO}_{3}\) are required for complete neutralization.
03

Use the mole ratio to find the moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\)

Since we know the moles of \(\mathrm{HNO}_{3}\) and the mole ratio of the reactants, we can determine the moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\) required to neutralize the given moles of \(\mathrm{HNO}_{3}\) using the following proportion: \[\frac{1 \, \text{mole} \, \mathrm{Ba}(\mathrm{OH})_{2}}{2 \, \text{moles} \, \mathrm{HNO}_{3}} = \frac{x \, \text{moles} \, \mathrm{Ba}(\mathrm{OH})_{2}}{2.5 \, \text{moles} \, \mathrm{HNO}_{3}}\]
04

Solve for x

Now we just need to solve for x to find the moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\) needed: \(x = \frac{1 \, \text{mole} \, \mathrm{Ba}(\mathrm{OH})_{2} \times 2.5 \, \text{moles} \, \mathrm{HNO}_{3}}{2 \, \text{moles} \, \mathrm{HNO}_{3}}\) \(x = 1.25 \, \text{moles} \, \mathrm{Ba}(\mathrm{OH})_{2}\) Hence, it takes \(1.25\) moles of \(\mathrm{Ba}(\mathrm{OH})_{2}\) to neutralize \(2.5\) moles of \(\mathrm{HNO}_{3}\).

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