An organic compound has the formula \(\mathrm{C}_{6} \mathrm{H}_{6}\) and it possesses three \(\mathrm{C}=\mathrm{C}\) double bonds. Draw it.

Short Answer

Expert verified
The organic compound with the formula \(\mathrm{C}_6\mathrm{H}_6\) and three carbon-carbon double bonds is benzene. Its structure can be drawn as: \( \begin{array}{c} \mathrm{H} \phantom{-} \\ | \phantom{-} \\ \mathrm{C}=\mathrm{C} - \mathrm{C} = \mathrm{C} - \mathrm{C} = \mathrm{C} \\[-9pt] | \phantom{-} \\ \mathrm{H} \phantom{-} \end{array} \)

Step by step solution

01

Draw a chain of six carbons

Start by drawing a straight chain of six carbon atoms bonded to each other in a line. \( \mathrm{C} - \mathrm{C} - \mathrm{C} - \mathrm{C} - \mathrm{C} - \mathrm{C} \)
02

Add the three carbon-carbon double bonds

To add the three carbon-carbon double bonds, we will convert three of the existing single bonds between adjacent carbons into double bonds. Adding double bonds in an alternating fashion allows for all carbon atoms to participate in double bonding. \( \mathrm{C} = \mathrm{C} - \mathrm{C} = \mathrm{C} - \mathrm{C} = \mathrm{C} \)
03

Attach the hydrogen atoms

To complete the structure of the organic compound, we need to attach the six hydrogen atoms. Each carbon atom should have a total of four bonds (sum of single and double bonds). Here's the final structure: \( \begin{array}{c} \mathrm{H} \phantom{-} \\ | \phantom{-} \\ \mathrm{C}=\mathrm{C} - \mathrm{C} = \mathrm{C} - \mathrm{C} = \mathrm{C} \\[-9pt] | \phantom{-} \\ \mathrm{H} \phantom{-} \end{array} \) Our final result is the structure of benzene, which is an organic compound with the empirical formula \(\mathrm{C}_{6}\mathrm{H}_{6}\) and three carbon-carbon double bonds.

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