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Chapter 17: Problem 47

Is the compound \(\mathrm{C}_{7} \mathrm{H}_{14}\) unsaturated or saturated? How can you tell?

Short Answer

Expert verified
The compound \(C_7H_{14}\) is unsaturated because its degree of unsaturation equals 1, which is a whole number greater than zero. This indicates that the compound has one double bond or one ring in its structure.

Step by step solution

01

Identify the number of carbon and hydrogen atoms in the compound

In the compound C7H14, there are 7 carbon atoms and 14 hydrogen atoms.
02

Use the degree of unsaturation formula

Using the degree of unsaturation formula, plug in the values for n and h: Degree of unsaturation = (2 * 7 + 2 - 14) / 2
03

Calculate the degree of unsaturation

Following the arithmetic operations, we get: Degree of unsaturation = (14 + 2 - 14) / 2 = 2 / 2 = 1
04

Determine if the compound is unsaturated or saturated

Since the degree of unsaturation is 1 (a whole number greater than zero), the compound C7H14 is unsaturated. It contains one degree of unsaturation, which means it has either one double bond or one ring in its structure.

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Most popular questions from this chapter

What is wrong with using common names for hydrocarbon molecules?

Are \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{H}_{2} \mathrm{O}_{2}\) isomers? Explain.

Explain why a carbon atom almost always forms four covalent bonds in a covalent substance. How is carbon monoxide an exception to this rule?

Although it was not discussed in the chapter, it is possible for a hydrocarbon molecule to have more than one site of unsaturation. One such molecule is 1,3 -butadiene; the \(d i\) - tells us there are two double bonds in the molecule. Give the molecular formula and line drawing for this molecule.

What endings are added to the root alk- to name hydrocarbons containing all \(\mathrm{C}-\mathrm{C}\) single bonds, hydrocarbons containing one or more \(\mathrm{C}=\mathrm{C}\) double bonds, and hydrocarbons containing one or more \(\mathrm{C} \equiv \mathrm{C}\) triple bonds?
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