Chapter 17: Problem 97

Draw all the isomers of the alcohols having the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\).

Short Answer

Expert verified

The isomers of the alcohols with the molecular formula C4H10O are: 1. 1-Butanol: \(CH_{3}-CH_{2}-CH_{2}-CH_{2}-OH\) 2. 2-Butanol: \(CH_{3}-CH_{2}-CH(OH)-CH_{3}\) 3. 2-Methyl-2-propanol: \(CH_{3}-C(CH_{3})_{2}-OH\) These isomers are generated by considering different carbon chain possibilities and attaching the hydroxyl (OH) group in various positions.

Step by step solution

Write down the carbon chain possibilities.

As there are 4 carbons in the molecular formula, we have the following carbon chain possibilities: 1. Butane (Straight chain): *C-C-C-C* 2. Isobutane (Branched): *C-C-C* | *C*

Generate the positional isomers of alcohols.

From the carbon chains mentioned in Step 1, we will now try to position the hydroxyl (OH) group: For Butane: 1. *C-C-C-C* 2. *C-C-C-C* First isomer: Attach the OH group on the first carbon in the straight chain. Second isomer: Attach the OH group on the second carbon in the straight chain. For Isobutane: 1. *C-C-C* | *C* Only one isomer is possible: Attach the OH group on the second carbon in the branched chain.

Draw the structural formulas of the isomers.

Now, we will draw the structural formulas for the isomers of C4H10O. 1. For the first isomer (1-Butanol): \[CH_{3}-CH_{2}-CH_{2}-CH_{2}-OH\] 2. For the second isomer (2-Butanol): \[CH_{3}-CH_{2}-CH(OH)-CH_{3}\] 3. For the third isomer (2-Methyl-2-propanol): \[CH_{3}-C(CH_{3})_{2}-OH\] These are all the possible isomers of the alcohols having the molecular formula C4H10O.

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Draw all the isomers of the alcohols having the molecular formula \(\mathrm{C}_{4} \mathrm{H}_{10} \mathrm{O}\).

Short Answer

Step by step solution

Write down the carbon chain possibilities.

Generate the positional isomers of alcohols.

Draw the structural formulas of the isomers.

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