Chapter 18: Problem 42
The DNA bases always hydrogen-bond in specific pairs. What are those pairs?
Chapter 18: Problem 42
The DNA bases always hydrogen-bond in specific pairs. What are those pairs?
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Get started for freeWhat two peptides are possible from the combination of alanine and glycine? Draw both of them.
In the olden days (the \(1970 \mathrm{~s})\), the sequence of amino acids in a protein was determined by running a series of chemical reactions known as the Edman degradation. This technique worked only on short peptide chains, however, and large proteins had to be broken down into small parts in order to be sequenced. One way to chop large proteins into small chains was with enzymes known as proteases. The protease trypsin breaks the amide bond on the \(\mathrm{CO}_{2} \mathrm{H}\) side of arginine and lysine, and the protease chymotrypsin breaks the amide bond on the \(\mathrm{CO}_{2} \mathrm{H}\) side of tyrosine, phenylalanine, and tryptophan. An octapeptide treated with trypsin breaks down to the peptides Ala-Gly-Trp-Gly-Lys and Thr-Val-Lys, and the same octapeptide treated with chymotrypsin breaks down to the peptides Gly-Lys and Thr-Val-Lys-Ala-Gly-Trp. What is the sequence of the octapeptide?
What is a polymer? How does it differ from a monomer?
How does glucose differ structurally from sucrose?
Amino acids are a sort of self-contradiction because they contain both a basic group (the \(\mathrm{NH}_{2}\) end) and an acidic group (the \(\mathrm{CO}_{2} \mathrm{H}\) end \()\) in the same molecule. Therefore, it should not surprise you that, when dissolved in water, an amino acid can react with itself to form what is known as a zwitterion. Based on this information, (a) Draw the structural formula for the form of the amino acid alanine you would expect to find in a neutral water solution. What is the net electrical charge on this species? (b) Enough concentrated \(\mathrm{HCl}\) is added to the solution of part (a) to make it strongly acidic. Draw the structural formula for the form of alanine you expect to find in this solution. What is the net charge on the alanine? (c) Enough concentrated \(\mathrm{NaOH}\) is added to the solution of part (a) to make it strongly basic. Draw the structural formula for the form of alanine you expect to find in this solution. What is the net charge on the alanine now?
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