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Chapter 2: Problem 103

A train traveling at \(45.0\) miles \(/ \mathrm{h}\) has to make a trip of \(100.0\) miles. How many minutes will the trip take? Use unit analysis to calculate your answer, and show your work.

Short Answer

Expert verified
The trip will take approximately \(133.33 \: \text{minutes}\).

Step by step solution

01

Write down the given values

Speed: \(45.0 \: \text{miles/h}\) Distance: \(100.0 \: \text{miles}\)
02

Find the time in hours

We can calculate the time taken in hours by using the formula time = distance / speed. Time (hours) = \(\frac{100.0 \: \text{miles}}{45.0 \: \text{miles/h}}\)
03

Calculate the time in hours

Time (hours) = \(\frac{100.0}{45.0}\) Time (hours) ≈ \(2.22 \: \text{hours}\)
04

Convert the time from hours to minutes

We can convert the time from hours to minutes by multiplying the time in hours by 60 (since there are 60 minutes in an hour). Time (minutes) = \(2.22 \: \text{hours} \times 60 \frac{\text{minutes}}{\text{hour}}\)
05

Calculate the total time in minutes

Time (minutes) = \(2.22 \times 60\) Time (minutes) ≈ \(133.33 \: \text{minutes}\) The trip will take approximately 133.33 minutes.

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Most popular questions from this chapter

If 1 U.S. dollar is worth \(0.690\) English pounds, how many U.S. dollars are needed to purchase an item that costs 350 pounds?

Convert: (a) \(2.37 \times 10^{2} \mathrm{~L}\) to milliliter (b) \(800 \mathrm{~kg}\) to grams (c) \(0.592 \mathrm{~mm}\) to meters (d) \(8.31 \mathrm{~g}\) to kilograms (e) \(9.62 \times 10^{-6} \mathrm{~L}\) to microliters (f) \(8000 \mathrm{~m}\) to kilometers (g) \(19.3 \mathrm{mg}\) to grams (h) \(0.00345 \mathrm{~mL}\) to liters

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